All categories

3 years ago

There are 20 chickens and 30 ate cows how many left over?

Mathematics

2 answers:

adoni [48]3 years ago

6 0

The answer is either 10 or 18
30-20=10
38-20-18

lesantik [10]3 years ago

4 0

38
-20
___
18 left over

You might be interested in

The math teacher gives each student a map of the amusement park that use a coordinate plane the meeting locates is at(0,0) on th

GrogVix [38]

Given:

Starting point = (0,0)

First ride = (0,4)

Second ride = (3,0)

In map, each unit = 100 ft

To find:

The actual distance between first and second ride.

Solution:

Distance formula: Distance between two points is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get the distance between first ride and second ride in the map is

$d=\sqrt{(3-0)^2+(0-4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d=5$

So, the distance between first ride and second ride in the map is 5 units.

We have,

1 units = 100 ft

5 units = 500 ft

The actual distance between first and second ride is 500 ft.

Therefore, the correct option is C.

5 0

3 years ago

What am I supposed to do here, I don't see a triangle.

ladessa [460]

Answer:

its the angle

Step-by-step explanation:

im pretty sure

4 0

3 years ago

A biologist observed that a certain bacterial colony obeys the population growth law and that the colony triples every 4 hours.

MrRa [10]

Answer:

a) $P(t) = 2e^{0.275t}$

b) 54.225 square centimeters.

c) 2.52 hours

Step-by-step explanation:

The population growth law is:

$P(t) = P_{0}e^{rt}$

In which P(t) is the population after t hours, $P_{0}$ is the initial population and r is the growth rate, as a decimal.

In this problem, we have that:

The colony occupied 2 square centimeters initially, so $P_{0} = 2$

The colony triples every 4 hours. So

$P(4) = 3P_{0} = 6$

(a) An expression for the size P(t) of the colony at any time t.

We have to find the value of r. We can do this by using the P(4) equation.

$P(t) = P_{0}e^{rt}$

$6 = 2e^{4r}$

$e^{4r} = 3$

Applying ln to both sides, we get:

$4r = 1.1$

$r = 0.275$

$P(t) = 2e^{0.275t}$

(b) The area occupied by the colony after 12 hours.

$P(t) = 2e^{0.275t}$

$P(12) = 2e^{0.275*12}$

$P(12) = 54.225$

(c) The doubling time for the colony?

t when $P(t) = 2P_{0} = 2*2 = 4$ .

$P(t) = 2e^{0.275t}$

$4 = 2e^{0.275t}$

$e^{0.275t} = 2$

Applying ln to both sides

$0.275t = 0.6931$

$t = 2.52$

4 0

3 years ago

Sidney has 4 hats and 2 scarves in a drawer. All the hats are the same size, shape, and material. Both scarves are the same size

hichkok12 [17]

Answer:

$P(White\ n\ Blue) = \frac{1}{8}$

Step-by-step explanation:

Given

Scarves: 1 green; 1 white

Hats: 1 blue; 1 red; 1 yellow; 1 purple

Required

Determine the probability of 1 blue hat and 1 white scarf

First, we need to determine the probability of blue hat

$Total\ Hats = 4$

$Blue\ Hats = 1$

Hence;

$P(Blue) = \frac{1}{4}$

Next, we determine probability of white scarf

$Total\ Scarfs = 2$

$White\ Scarfs = 1$

$P(White) = \frac{1}{2}$

Calculating the required probability;

$P(White\ n\ Blue) = P(White) * P(Blue)$

$P(White\ n\ Blue) = \frac{1}{4} * \frac{1}{2}$

$P(White\ n\ Blue) = \frac{1}{8}$

6 0

3 years ago

JUST A RIDDLE...............................

jasenka [17]

Answer:

2 tickets

Step-by-step explanation:

hope it is right

7 0

3 years ago

Read 2 more answers