sin θ = 3 / 7 = .429
sin^2 θ + cos^2 θ = 1 trig identity
9/49 + cos^2 θ = 1
cos^2 θ = 40 / 49 = .816 cos θ = .903
Check .429^2 + .903^2 = 1
cos .903 = 25.4 deg
In the second quadrant sin = +, cos = -, tan = -
So 25.4 deg in the second quadrant = 180 - 25.4 = 154.6 deg
Check:
sin 154.6 = .428
cos 154.6 = -.903
tan 154.6 = -.475
<span>a. Write and graph a system of linear inequalities
Here's the equation of a system of linear inequalities.
x >= 80
2x + 2y <= 300 -----> y <= -x + 150
For the graph, it is attached as image.
</span>b. Write two possible solutions:<span>These are the two possible solutions to the given equation of linear inequality.
90 feet by 20 feet
110 feet by 30 feet.</span>
We know the first term is 16, because f(1) = 16. Next, we can use the recursive rule provided. f(3)=1/2*f(3-1). This gives us f(3)=1/2*f(2). We know f(2) is 8. We know have f(3)=1/2*8. This is 4.
The answer is 16, 4.
Parallel lines have same slope, so first isolate y to get the equation into y=mx+b form.
-2x+3y=2
3y = 2x + 2

Now plug the point (3,4) into y = 2x + b
4 = 2(3) + b
Solves for be
b = -2
So the new equation is y = 2x - 2