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Mama L [17]
3 years ago
15

Jamila earns $14,$11,$20,$15,$20 from babysitting 5 times. Find the median

Mathematics
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

15

Step-by-step explanation:

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3. What is the decimal equivalent of each
zaharov [31]

Answer:

a. 0.81818182

b. 0.8

c. -3.4

d. 0.55555556

Step-by-step explanation:

8 0
3 years ago
Answer ASAP, will give brainliest
Eduardwww [97]

Answer:

A) 5.4 cm

Step-by-step explanation:

Length of mid segment = (sum of parallel sides )/2

Sum of parallel sides = PQ + SR = 9 + SR

\frac{9+SR}{2}=MN\\\\\frac{9+SR}{2}=7.2 cm\\9 +SR = 7.2*2\\\\9 + SR = 14.4\\       SR = 14.4 -9 \\SR = 5.4 cm

4 0
3 years ago
Jenna is drawing a sketch of her room. The room is 15 feet long by 12 feet wide. The
SOVA2 [1]

Answer:

4 inches

Step-by-step explanation:

Actual dimensions:

Length = 15 feet

Width = 12 feet

Scale dimensions:

Length = 5 inches

Width = x inches

Write a proportion:

\dfrac{\text{Actual length}}{\text{Scale length}}=\dfrac{\text{Actual width}}{\text{Scale width}}\\ \\ \\\dfrac{15\ feet}{5\ inches}=\dfrac{12\ feet}{x\ inches}\\ \\x=\dfrac{5\ inches\times 12\ feet}{15\ feet}=4\ inches

3 0
4 years ago
Three boxes are stacked one on top of each other one box is 2 feet 11 inches tall one is 3 feet 5 inches tall and one is 4 feet
Natasha_Volkova [10]

Answer:

<u>11 feet 2 inches</u>

Step-by-step explanation:

ill add the inches first

11+5+10= 26

26inches= 2ft 2inches

now I add the feet

2+3+4+2=11 feet

<u>11 feet 2 inches</u>

7 0
2 years ago
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that p = 0.95

10 targets

This means that n = 10

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

P(X = 10) + P(X < 10) = 1

We want P(X < 10). So

P(X < 10) = 1 - P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401

40.1% probability that he will miss at least one of them

7 0
3 years ago
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