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marissa [1.9K]
3 years ago
13

Find the least common multiple of x² + x – 12 and x² + 2x – 15.

Mathematics
2 answers:
Pani-rosa [81]3 years ago
5 0

Answer:

Least common multiple (x-3) ( x+5) (x +4 ).

Step-by-step explanation:

Given :  x² + x – 12 and x² + 2x – 15.

To find : Find the least common multiple.

Solution : We have given that : x² + x – 12 and x² + 2x – 15.

First : x² + x – 12

On factoring x² + 4x-3x – 12.

Taking common x (x +4 ) -3( x+4 )

(x -3 ) (x +4 )

For : x² + 5x -3x  – 15.

Taking common x (x+5) -3( x +5)

(x-3) ( x+5)

Therefore, Least common multiple (x-3) ( x+5)(x +4 ).

ioda3 years ago
4 0

Solution:

we have been asked to find the Least Common multiple of the given polynomial x² + x – 12 and x² + 2x – 15.

To find the least common multiple. Lets first find the factors.

x^2+x-12=x^2+4x-3x-12\\ \\ x^2+x-12=x(x+4)-3(x+4)\\ \\ x^2+x-12=(x+4)(x-3)\\

x^2+2x-15=x^2+5x-3x-15\\ \\ x^2+2x-15=x(x+5)-3(x+5)\\ \\ x^2+2x-15=(x+5)(x-3)\\

Hence the LCM of the given set of Polynomials is (x+4)(x-3)(x+5).

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Answer:

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Step-by-step explanation:

distribute -7 into (4n+8)

-10n+50=-28n-56-2

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-10n+50=-28n-58

add -28n on both sides

-10n+28n+50=-58

combine like terms again

18n+50=-58

subtract 50 on both sides

18n=-108

divide both sides by 18

\frac{18x}{18} =\frac{-108}{18}

x=-6

hope this helps

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8 0
3 years ago
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7 0
3 years ago
What is the product of 4xy and y2 + 2x?
juin [17]
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3 0
3 years ago
Find the quadratic function y=​f(x) whose graph has a vertex ​(−3​,4​) and passes through the point ​(−7​,0). Write the function
olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.  

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

a=-\frac{1}{4}

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

And there you go!

5 0
3 years ago
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