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zvonat [6]
3 years ago
13

Write a formula to find the nth term of a geometric sequence -1/3,1/2,-3/4,9/8​

Mathematics
1 answer:
podryga [215]3 years ago
4 0

Answer:

Step-by-step explanation:

first term a = -1/3

Ratio r = 1/2÷ (-1/3) = 1/2 * (-3/1) =  -3/2

nth term = ar^(n-1)

=(-1/3)*(-3/2)^(n-1)

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98 divided by 2 equals 49 55 divided by 5 equals 11
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4 years ago
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Someone ask me to solve this.
Semenov [28]
X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 ----->  3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

 3k +4h =4          ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4  or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4  , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3 

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .




6 0
3 years ago
Given: f(x) = x - 7 and h(x) = 2x + 3
LenKa [72]

<u>ANSWER</u>


h(f(x))=2x-11


<u>EXPLANATION</u>


Given f(x)=x-7


and

h(x)=2x+3


We want to find


h(f(x))=h(x-7)

This means we substitute the function f in to another function h and evaluate.

This implies that;

h(f(x))=2(x-7)+3


We expand the parenthesis to obtain;


h(f(x))=2x-14+3

We simplify further to obtain;

h(f(x))=2x-11


Hence the correct answer is A

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Answer:

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marishachu [46]

Answer:

-3, 4

Step-by-step explanation:

(x+3)(x-4)=0

Therefore, x + 3 = 0 and x - 4 = 0

so, x = -3 and x = 4

6 0
4 years ago
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