Answer:
The probability P of a day with no perceptible earthquakes is 0.0821.
Step-by-step explanation:
We will consider that earthquakes occurring in a day is a <u>Poisson process</u>. The following Poisson probability distribution formula will be used in this question.
<u>p(x,λ) = [e^-λ (λ)ˣ]/x!</u>
where x = number of outcomes occurring
λ = mean number of occurrences
(a) So, in this question we have λ = 2.5 and we need to find the probability that x=0 (no perceptible earthquakes in a day). So,
P(X=0) = p(0,2.5) = [(e^-2.5)(2.5)⁰]/0!
= ((0.0821)*1)/1
P(X=0) = 0.0821
The probability P of a day with no perceptible earthquakes is 0.0821.
X^2+y^2-6x+2y-36=0. Use the equation of the circle (x-h)^2+(y-k)^2=radius^2, center (h,k) is (3,-2)
555 Oatmeal Raisin Cookies
1,850 / 0.30 = 555
I Hope This Helps! (^_^)
Answer:
5.9 years.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean 
and standard deviation 
In this question:
Mean of the population is 
If a sampling distribution is created using samples of the ages at which 69 children begin reading, what would be the mean of the sampling distribution of sample means?
By the Central Limit Theorem, the same population mean, of 5.9 years.
