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4 years ago

Please Help me with question

Mathematics

1 answer:

pashok25 [27]4 years ago

6 0

The answer is three what you simply do is just look at what is dividable by the two answers so 12÷3 for 24÷8 for and so on

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Question 10: If the product of all the numbers from 1 to 100 is divisible by 2^n, then what is the maximum possible value for n:

Klio2033 [76]

Answer: D

Step-by-step explanation:

100!=2*3*4*...*100

Counting which numbers are divisible by 2:

2,4,6,8,10,12,14,...,96,98,100 : 50 numbers (100/2=50)

Counting which numbers are divisible by 4=2²:

4,8,12,16,20,...96,100: 25 numbers (100/4=25)

Counting which numbers are divisible by 8=2³:

8,16,24,32,40,...,96: 12 numbers (100/8=12.5 ==> 12)

Counting which numbers are divisible by 16=2⁴:

16,32,48,...,96: 6 numbers (100/16=6.25 ==> 6)

Counting which numbers are divisible by 32=2⁵:

32,64,96 : 3 numbers(100/32=3.125 ==>3)

Counting which numbers are divisible by 64=2⁶:

64 : 1 number (100/64=1.5625 ==>1)

Sum of those numbers= 50+25+12+6+3+1=97

100! is divisible by 2⁹⁷.

Answer D

4 0

3 years ago

Read 2 more answers

Use the power reducing formula to rewrite the expression in therms of first powers of hte cosines of ultiple angles 3cos^4x.

Oxana [17]

The particular identity you want to use is

$\cos^2x=\dfrac{1+\cos(2x)}2$

Then

$3\cos^4x=3(\cos^2x)^2=3\left(\dfrac{1+\cos(2x)}2\right)^2=\dfrac34(1+\cos(2x))^2$

Expand the binomial to get

$3\cos^4x=\dfrac34\left(1+2\cos(2x)+\cos^2(2x)\right)$

Use the identity again to write

$\cos^2(2x)=\dfrac{1+\cos(4x)}2$

and so

$3\cos^4x=\dfrac34\left(1+2\cos(2x)+\dfrac{1+\cos(4x)}2\right)$

$3\cos^4x=\dfrac38\left(3+4\cos(2x)+\cos(4x)\right)$

7 0

3 years ago

I am a two-digit even number. I am

Tom [10]

The answer is 80 because 8>0 80 is a multiple of 5, it’s even and it a two digit number

8 0

3 years ago

Jane buys candy that cost $8 per pound. She will spend more than $48 on candy. What are the possible numbers of pounds she will

Blizzard [7]

Answer:6

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the value of cos E rounded to the nearest hundredth, if necessary. please help thanks

bonufazy [111]

Answer:

cos(E)=0.8

Step-by-step explanation:

cos(E)=adjacent/hypotenuse

Using a common pythagorean triple, we can find that side GE is 30 (18^2+24^2=30^2)

Then we just get cos(E)=24/30, which is 0.8

4 0

2 years ago