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patriot [66]
3 years ago
8

In a cathode ray tube, the number of electrons that reach the fluorescent screen is controlled by the

Physics
2 answers:
disa [49]3 years ago
7 0

Answer: B. GRID

Explanation: I JUST TOOK THE PF EXAM AND GOT IT CORRECT!!!!

Lana71 [14]3 years ago
6 0
In a cathode ray tube, the number of electrons that reach the fluorescent screen is controlled by the grid. The correct option among all the options given in the question is option "B".When current is supplied to the heater, it causes the cathode to emit electrons. The electrons pass through opening of the grid before reaching the anode. By controlling the number of electrons passing through the grid, the number of electrons reaching the anode can also be controlled.<span> 
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How was the speed of light determined
goblinko [34]
Presently, the speed of light in a vacuum is defined to be exactly 299,792,458 m/s (approximately 186,282 miles per second). . An early experiment to measure the speed of light was conducted by Ole Romer, a Danish physicist, in 1676. Using a telescope, Ole observed the motions of Jupiter and one of its moons, Io
5 0
3 years ago
Read 2 more answers
A car accelerates from rest at 3 m/s for 6 seconds. The velocity of the car after 6 seconds is what ?
Artist 52 [7]

vf = vi + at
then solve for v

so
v = a(t)
so v = (3m/s^2)(6s)

so v = 18m/s

5 0
3 years ago
Which term refers to the rate at which the velocity of a moving object changes? A.acceleration B.displacement C.resonance D.turb
Inessa [10]
A. Acceleration is the answer to you question. When an object changes velocity it can accelerate.<span />
4 0
4 years ago
A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio
Gnesinka [82]

Answer:

a).a_p=-2.39x10^{-12} rad/s^2

b).t=1016298.8 years

c).T_i=80.58x10^{-3}s

Explanation:

a).

The acceleration for definition is the derive of the velocity so:

a_p=\frac{dw}{dt}

w=\frac{2\pi}{t}

a_p=\frac{dw}{dt}=-\frac{2\pi}{t^2}*\frac{dT}{dt}

dT=0.0808s

dt=1 year*\frac{365d}{1year} \frac{24hr}{1d} \frac{60minute}{1hr} \frac{60s}{1minute}=31.536x10^{6}s

Replacing

a_p=-\frac{2\pi}{0.082s^2}*\frac{9.84x10^{-7}}{31.536x10^{6}s}= -2.39x10^{-12} rad/s^2

b).

If the pulsar will continue to decelerate at this rate, it will  stop rotating at time:

t=\frac{w}{a_p}

w=\frac{2\pi }{t}=\frac{2\pi }{0.0820s}=76.62 rad/s

t=\frac{76.62 rad/s}{2.39x10^{-12}rad/s^2}= 3.2058x10^{13}s

t=1016298.8 years

c).

582 years ago to 2019

1437

T_i=0.0820-9.84x10^{-7}*1437)=80.58x10^{-3}s

5 0
4 years ago
Which of the following statements about diodes and triodes is correct
nata0808 [166]
There are no correct statements on your list.
4 0
3 years ago
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