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patriot [66]
3 years ago
8

In a cathode ray tube, the number of electrons that reach the fluorescent screen is controlled by the

Physics
2 answers:
disa [49]3 years ago
7 0

Answer: B. GRID

Explanation: I JUST TOOK THE PF EXAM AND GOT IT CORRECT!!!!

Lana71 [14]3 years ago
6 0
In a cathode ray tube, the number of electrons that reach the fluorescent screen is controlled by the grid. The correct option among all the options given in the question is option "B".When current is supplied to the heater, it causes the cathode to emit electrons. The electrons pass through opening of the grid before reaching the anode. By controlling the number of electrons passing through the grid, the number of electrons reaching the anode can also be controlled.<span> 
</span>
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Each of the following figures shows Earth with a different axis tilt. (Assume that Earth's rotation period is unchanged.) Each a
mart [117]

Answer:

 0º - 23.5º - 45º - 90º

Explanation:

The inclination angle of the Earth's axis with respect to its orbit around the Sun, determines that the duration enters the day and the night is different.

If it is not inclined (angle 0º) the two and niches have the same hardness

If the angle were very high (about 90º) the night would be very long, about half of the orbit period about six months.

Based on this presentation we can answer the question

The Sumo exposition from highest to lowest is

    0º - 23.5º - 45º - 90º

3 0
3 years ago
Your friend's 10.8 g graduation tassel hangs on a string from his rearview mirror. When he accelerates from a stoplight, the tas
Nitella [24]

The tension in the string holding the tassel and the vertical will the tension in the string

  • T = 0.1953 N
  • Ф = 34.4 °

<h3>What is the tension in the string holding the tassel. ?</h3>

Generally, the equation for Tension is  mathematically given as

TCos\theta = mg

Therefore

TCos6.58^{o} = 19.8*10^{-3}*9.8

T = 0.1953 N

b).

Where

T* sin \theta = ma

0.1953*Sin6.58 \textdegree  = 19.8*10^{-3}*a

a = 1.13 m/s^2

In conclusion

T* sinФ = ma

2msinФ = ma

2sinФ = a

sin\theta = \frac{a}{2}

\theta = sin^{-1}\frac{a}{2} \\\\\theta= sin^{-1}\frac{1.13}{2}

Ф = 34.4 °

In conclusion, The tension in the string holding the tassel and the vertical will the tension in the string

T = 0.1953 N

Ф = 34.4 °

Read more about tension

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4 0
2 years ago
Definition electromagnetic spectrum
Irina-Kira [14]
The spectrum in which the frequency and wavelength of electromagnetic radiation fall into in relation to each other.
3 0
3 years ago
Two long, straight wires are parallel and are separated by a distance of d = 0.210 m. The top wire in the sketch carries current
love history [14]

Answer:

1.88\cdot 10^{-5} T, inside the plane

Explanation:

We need to calculate the magnitude and direction of the magnetic field produced by each wire first, using the formula

B=\frac{\mu_0 I}{2\pi r}

where

\mu_0 is the vacuum permeability

I is the current

r is the distance from the wire

For the top wire,

I = 4.00 A

r = d/2 = 0.105 m (since we are evaluating the field half-way between the two wires)

so

B_1 = \frac{(4\pi\cdot 10^{-7})(4.00)}{2\pi(0.105)}=7.6\cdot 10^{-6}T

And using the right-hand rule (thumb in the same direction as the current (to the right), other fingers wrapped around the thumb indicating the direction of the magnetic field lines), we find that the direction of the field lines at point P is inside the plane

For the bottom wire,

I = 5.90 A

r = 0.105 m

so

B_2 = \frac{(4\pi\cdot 10^{-7})(5.90)}{2\pi(0.105)}=1.12\cdot 10^{-5}T

And using the right-hand rule (thumb in the same direction as the current (to the left), other fingers wrapped around the thumb indicating the direction of the magnetic field lines), we find that the direction of the field lines at point P is also inside the plane

So both field add together at point P, and the magnitude of the resultant field is:

B=B_1+B_2 = 7.6\cdot 10^{-6} T+1.12\cdot 10^{-5}T=1.88\cdot 10^{-5} T

And the direction is inside the plane.

3 0
3 years ago
Two stones are dropped from the edge of a 60m cliff , the second stone 1.6secon after the first . How far below the top of the c
tigry1 [53]

Answer:

The separation between the two stones is 36 m, when the second stone is approximately 10.9 m below the top of the cliff

Explanation:

The given parameters are;

The height of the cliff from which the stones are dropped, h = 60 m

The time at which the second stone is dropped = 1.6 seconds after the first

The distance below the top of the cliff when the distance between the two stones is 36 m = Required

We have;

The kinematic equation of motion that can be used is s = u·t - (1/2)·g·t²

For the first stone, we have, s₁ = u·t₁ - (1/2)·g·t₁²

For the second stone, we get; s₂ = u·t₂ - (1/2)·g·t₂²

t₁ = t₂ + 1.6

g = The acceleration due to gravity ≈ 9.81 m/s²

s = The distance below the cliff top

The initial velocity of the stones, u = 0

Let<em> t</em> represent the time from which the second stone is dropped at which the distance between the two stones is 36 m, we have;

s₁ = u·(t + 1.6) + (1/2)·g·(t + 1.6)²

s₂ = u·t + (1/2)·g·t²

u = 0

∴ s₁ - s₂ = 36 =  (1/2)·g·(t + 1.6)² - (1/2)·g·t²

2 × 36/(g) = (t + 1.6)² - t²  = t² + 3.2·t + 2.56 - t² = 3.2·t + 2.56

2 × 36/(9.81) = 3.2·t + 2.56

t = (2 × 36/(9.81) - 2.56)/3.2 =  ≈ 1.49 s

t ≈ 1.49 s

s₂ = (1/2)·g·t²

∴ s₂ = (1/2) × 9.81 × 1.49² ≈ 10.9

The distance below the top of the cliff of the second stone when the the separation between the two stones is 36 m, s₂ ≈ 10.9 m.

5 0
3 years ago
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