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3 years ago

In Milgram's experiment, compliance, or doing what the experimenter asked,

Physics

2 answers:

-BARSIC- [3]3 years ago

8 0

Answer:

Option C

Explanation:

In his experiment, Milgram wanted to test the extent of obedience a person can go as per the instructions of the authority.

In this he concluded the experiment saying that several factor when changed in the second round of experiment led to the dropping of obedience level and these factors are as follows –

a) Conducting the experiment at some ordinary place instead of Yale university campus

b) When the teachers were asked to force the hand of learner to touch the shock plate and they were placed in the same room

c) Two participants in the same room – If one participants showed disobedience then the other participant’s disobedience level will fall automatically

d) When the authority giving instructions is not nearby or is absent

Hence, option C is correct

Orlov [11]3 years ago

5 0

Answer:

In Milgram's experiment, compliance, or doing what the experimenter asked,

the teacher and the learner were in the same room. -C.

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Coherent light with wavelength 598 nm passes through two very narrow slits, and the interference pattern is observed on a screen

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Answer:

1.196 μm

Explanation:

D = Screen distance = 3 m

$\lambda$ = Wavelength = 598 m

y = Distance of first-order bright fringe from the center of the central bright fringe = 4.84 mm

d = Slit distance

$tan\theta=\frac{y}{D}\\\Rightarrow \theta=tan^{-1}{\frac{y}{D}}\\\Rightarrow \theta=tan^{-1}{\frac{4.84\times 10^{-3}}{3}}\\\Rightarrow \theta=0.09243\ ^{\circ}$

$sin\theta=\frac{\lambda}{d}\\\Rightarrow d=\frac{\lambda}{sin\theta}\\\Rightarrow d=\frac{598\times 10^{-9}}{sin0.09243}\\\Rightarrow d=0.00037066\ m$

For first dark fringe

$dsin\theta=\frac{\lambda'}{2}\\\Rightarrow \lambda'=2dsin\theta\\\Rightarrow \lambda'=2\times 0.00037066\times sin0.09243\\\Rightarrow \lambda'=1.196\times 10^{-6}\\\Rightarrow \lambda'=1.196\ \mu m$

Wavelength of first-order dark fringe observed at this same point on the screen is 1.196 μm

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3 years ago

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Explanation:

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