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2 years ago

In Milgram's experiment, compliance, or doing what the experimenter asked,

Physics

2 answers:

-BARSIC- [3]2 years ago

8 0

Answer:

Option C

Explanation:

In his experiment, Milgram wanted to test the extent of obedience a person can go as per the instructions of the authority.

In this he concluded the experiment saying that several factor when changed in the second round of experiment led to the dropping of obedience level and these factors are as follows –

a) Conducting the experiment at some ordinary place instead of Yale university campus

b) When the teachers were asked to force the hand of learner to touch the shock plate and they were placed in the same room

c) Two participants in the same room – If one participants showed disobedience then the other participant’s disobedience level will fall automatically

d) When the authority giving instructions is not nearby or is absent

Hence, option C is correct

Orlov [11]2 years ago

5 0

Answer:

In Milgram's experiment, compliance, or doing what the experimenter asked,

the teacher and the learner were in the same room. -C.

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3 years ago

With thermodynamics, one cannot determine ________. Question 6 options: the speed of a reaction the direction of a spontaneous r

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3 years ago

A bead slides without friction around a loop the-loop. The bead is released from a height of 17.6 m from the bottom of the loop-

solong [7]

Answer:

N₁ = 393.96 N and N = 197.96 N

Explanation:

In This exercise we must use Newton's second law to find the normal force. Let's use two points the lowest and the highest of the loop

Lowest point, we write Newton's second law n for the y-axis

N -W = m a

where the acceleration is ccentripeta

a = v² / r

N = W + m v² / r

N = mg + mv² / r

we can use energy to find the speed at the bottom of the circle

starting point. Highest point where the ball is released

Em₀ = U = m g h

lowest point. Stop curl down

$Em_{f}$ = K = ½ m v²

Emo = Em_{f}

m g h = ½ m v²

v² = 2 gh

we substitute

N = m (g + 2gh / r)

N = mg (1 + 2h / r)

let's calculate

N₁ = 5 9.8 (1 + 2 17.6 / 5)

N₁ = 393.96 N

headed up

we repeat the calculation in the longest part of the loop

-N -W = - m v₂² / r

N = m v₂² / r - W

N = m (v₂²/r - g)

we seek speed with the conservation of energy

Em₀ = U = m g h

final point. Top of circle with height 2r

$Em_{f}$ = K + U = ½ m v₂² + mg (2r)

Em₀ = Em_{f}

mgh = ½ m v₂² + 2mgr

v₂² = 2 g (h-2r)

we substitute

N = m (2g (h-2r) / r - g)

N = mg (2 (h-r) / r 1) = mg (2h/r -2 -1)

N = mg (2h/r - 3)

N = 5 9.8 (2 17.6 / 5 -3)

N = 197.96 N

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2 years ago