In Milgram's experiment, compliance, or doing what the experimenter asked,
2 answers:
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Answer:
C) It increases to 2.0 cm
Explanation:
In a double-slit diffraction experiment, the distance on the screen between two adjacent maxima is given by
where
is the wavelength of the wave
D is the distance of the screen from the slits
d is the separation between the slits
In this problem, the initial distance between adjacent maxima is 1.0 cm. Later, the slit separation is cut in a half, which means that the new slit separation is
Substituting into the equation, we find that the new separation between the maxima is
So, the distance increases by a factor 2: therefore, the new separation between the maxima will be 2.0 cm.
Answer
given,
x(t) = A t + B t²
A = -4.1 m/s
B = 5.4 m/s²
a) velocity of the particle is equal to the differentiation of Position w.r.t. time
the above equation gives the function of velocity.
b) time at which velocity of particle is zero
v = -4.1 + 10.8 t
inserting v = 0 and calculating v
0 = -4.1 + 10.8 t
10.8 t = 4.1
t = 0.38 s
time at which velocity is zero is equal to 0.38 s.