<h2>
Answer:</h2>
105146 Pa
<h2>
Explanation:</h2>
1) We will make a Free-Body Diagram representing all the upward and downward pressures exerted on the piston.
- Pressure exerted by the compressed spring (Pspring)
- Pressure due to weight of the piston (Pw)
- Atmospheric pressure (Patm)
- Initial pressure inside the cylinder. (P1)
2) We will formulate an equation balancing all upward and downward pressures.
P1= Patm + Pw + Pspring
3) We will calculate each of the pressures separately.
P = F/A
F= ks
k= 38×1000 =38000 N m
s= 2.5 /1000 = (2.5x10^-3) m
F = 38000×(2.5x10^-3) = 95 N
A = 30/10000 = (30x10^-4) m2
P = 95 / (30x10^-4)
Pspring ≅ 3167 Pa
P = F/A
F = W = mg
W = 2×9.81 = 19.62 N
A = 30/10000 = (30x10^-4) m2
P = 19.62 / (30x10^-4)
Pw = 654 Pa
P = 1atm = 101325 Pa
Patm = 101325 Pa
4) We will add all the downward pressures to reach the final answer (initial pressure inside the cylinder).
P1= Patm + Pw + Pspring
P1= 101325+654+3167
P1= 105146 Pa
Answer:
Radiation
Explanation:
radiation is The emission of energy as electromagnetic waves or as moving subatomic particles, especially high-energy particles which cause ionization.
Convection is within liquids, like boiling water.
Conduction is in solids, like leaving a metal fork in a hot pan.
...Brainliest?
<u>Answer:</u> The molar mass of metal (M) is 47.86 g/mol
<u>Explanation:</u>
Let the atomic mass of metal (M) be x
Atomic mass of
To calculate the mass of metal, we use the equation:
Mass percent of metal = 59.93 %
Mass of metal = x g/mol
Mass of metal oxide = (x + 32) g/mol
Putting values in above equation, we get:
Hence, the molar mass of metal (M) is 47.86 g/mol
He's accelerating at 3 m/s² .
That means his speed is increasing by 3 m/s every second.
At the end of 8 seconds, his speed is (8 x 3 m/s) = 24 m/s .
He's been moving south for the whole 8 seconds.
So at the end of that time, his velocity is
24 m/s south .
Answer:
1.2kV
Explanation:
We are given that
Linear charge density,
We have to find the potential difference between poinst 5.0 m and 6.0 m from the wire.
We know that potential difference of wire
Where
Substitute the values
1kV=1000 V