All categories

3 years ago

75 POINTS ASAP HELP

2 answers:

8 0

An exponential function repeatedly multiplies an initial amount by the same positive number called the constant ratio. For example, this is commonly used in geometric sequences and the constant ratio is the ratio between all the numbers in the sequence. I will put an example below:

Find the constant ratio of the geometric sequence:

2, 4, 8, 16, 32, 64

Divide each number to the one before it.

4 / 2 = 2

8 / 4 = 2

16 / 8 = 2

32 / 16 = 2

64 / 32 = 2

So, the constant ratio is 2 between all the numbers.

Best of Luck!

katrin2010 [14]3 years ago

3 0

Answer:

It is called the constant ratio.

You might be interested in

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

3 0

3 years ago

Math help me))))))))please

olasank [31]

X^2/(x- 9 = 81/(x - 9)
This is the equation for which you want the solution.
Multiplying both sides of the equation by (x - 9) we get
x^2(x - 9)/(x - 9) = 81(x - 9)/(x - 9)
So the (x - 9) goes out from both the denominator and the numerator and then the simplified equation becomes
x^2 = 81
x ^2 = (9)^2
x = 9
So the value of the unknown variable x comes out to be 9.

6 0

3 years ago

Read 2 more answers

Answer with A B C D. Correct answer gets brainlest.

oksian1 [2.3K]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

This figure shows △XYZ . MZ is the angle bisector of ∠YZX .

frosja888 [35]