Answer:
-1<b<7, or i suppose b.
Step-by-step explanation:
6b<42
b<7
4b+12>8
4b>-4
b>-1
Answer:
4213
Step-by-step explanation:
go to the numbers that pop out and do it backwards.
Answer:
Probability that a car need to be repaired once = 20% = 0.20
Probability that a car need to be repaired twice = 8% = 0.08
Probability that a car need to be repaired three or more = 2% = 0.02
a) If you own two cars what is the probability that neither will need repair?
Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3
Probability that car need no repair = 1-0.3=0.7
Neither car will need repair=
b) both will need repair?
Probability both will need repair = 
c)at least one car will need repair
Neither car will need repair=
Probability that at least one car will need repair= 1-0.49 = 0.51
Answer:
a) 8x+6a
b)5q+7q
Step-by-step explanation:
a) we need to combine the like(same) terms(with same variable) together
same terms: 3x and 5x
2a and 4a
so
3x+5x=8x
2a+4a=6a
8x+6a
b)a) we need to combine the like(same) terms together
same terms: 7p-2p=5q
6q+q=7q