Um sounds nice i guess its kind of funny simplify hairy fractions
Answer:15/17
Step-by-step explanation: cos = adjacent/hypotenuse
The answer on a app i have says it’s -3x - 7 so the person above me is right
Answer:
See Explanation
Step-by-step explanation:
Given
Base Dimension


Required
The base area of all containers
First, calculate the base area of 1 container.
This is calculated as:


Express as improper fraction

So, we have:


The number of containers is not given. So, I will use 'n' as the number of containers.
So, we have:


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Assume n is 3 (i.e. 3 containers)
The total area is:



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The function F(x) have a vertical asymptote at x =0 and x =1.
Given that
The given Function;

We have to determine
At which value the function F(x) has a vertical asymptote.
According to the question
The given Function;

The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:
Then,


The value of x is 0 and 1.
Hence, the function F(x) have a vertical asymptote at x =0 and x =1.
To know more about Parabola click the link given below.
brainly.com/question/12868913