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Vinil7 [7]
2 years ago
12

the diagram shows a circle inscribed in a square find the area of the shaded region of the side length of the square is 6 meters

.
Mathematics
1 answer:
ANTONII [103]2 years ago
6 0
24 hope it helps for you
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Find d. Write your answer in simplest radical form.
vekshin1

Answer:

d=8km

Step-by-step explanation:

explanation is in the image above

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WILL MARK BRAINLIEST!!!
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f(x) = -9x^4 + 5x + 3\\\\ f(-x)= -9(-x)^4 + 5\cdot(-x) + 3=-9x^4-5x+3\\\\ f(-x)\not =f(x)\implies \text{ not even}\\\\ -f(x)=-( -9x^4 + 5x + 3)= 9x^4 - 5x - 3\\\\ -f(x)\not =f(-x) \implies \text{ not odd}

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Which graphs display a directly proportional relationship? Check all that apply.
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V125BC [204]

Answer:

2. ΔABC is isosceles

Step-by-step explanation:

Given : m∠A = 50

m∠BCD = 180 - (m∠BDC + m∠DBC)

              = 180 - (100 + 30)

              = 50

then

m∠A = m∠BCD

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6 0
3 years ago
I need help!! Find the area of each shaded segment. Round your answer to the nearest 10th
guajiro [1.7K]

Given:

θ = 60°

Radius = 8 in

To find:

The area of the shaded segment.

Solution:

Vertically opposite angles are congruent.

Angle for the shaded segment = 60°

<u>Area of the sector:</u>

$A=\pi r^2\times \frac{\theta}{360^\circ}

$A=3.14 \times 8^2\times \frac{60^\circ}{360^\circ}

A = 33.5 in²

Area of the sector = 33.5 in²

<u>Area of triangle:</u>

$A=\frac{1}{2} bh

$A=\frac{1}{2} \times 8\times 8

A = 32 in²

Area of the triangle = 32 in²

Area of segment = Area of sector - Area of triangle

                            = 33.5 in² - 32 in²

                            = 1.5 in²

The area of the shaded segment is 1.5 square inches.

8 0
3 years ago
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