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gavmur [86]
3 years ago
13

On a typical day flights at a local airport arrive at a rate of 10 every 15 minutes. At this rate how many flights would you exp

ect in 1 hour?

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0
There are 4 sets of 15 minutes in a hour so you would take the 10 airplanes and multiply it by 4 and get 40 as your answer
In 1 hour 40 planes with arrive at the airport
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Why is the power in the united states dived between several branches
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Answer:

To ensure that they all have the equal amount of power; to make sure one branch doesn't have more power than the others.

6 0
3 years ago
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Find the slope of the line through each pair of points.
Fudgin [204]
<h2>Answer:    slope = ¹¹/₁₃ </h2><h3>Step-by-step explanation:    </h3>

      The question gives us two points, (−13, −19) & (13, 3), from which we can find the slope and later the equation of the line.

Finding the Slope

The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)      

                                          =  ((3 - (-19)) ÷ (13 - (-13))      

                                          =   22 ÷ 26

                                          =  ¹¹/₁₃

<em></em>

<em></em>

<em>Checking my answer:</em>

<em>We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line. If the line passes through both of the points then we calculated the slope correctly.</em>

                                ⇒  y + 19 =  ¹¹/₁₃ (x + 13)

<em>I have included a Desmos Graph that I graphed using the information equation (including the slope) and the points given. </em>

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3 years ago
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3 years ago
What is the value of -32+(-4+7)(2)?<br> -28<br> -3<br> 3<br> 15
I am Lyosha [343]

Answer:

-26

Step-by-step explanation:

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  3. -26

By using BODMAS, any of the answers given is correct!

6 0
2 years ago
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Which shows the expression below in simplified form? (7.2 × 107) ÷ (9 × 104) A. 8 × 101 B. -1.8 × 102 C. 8 × 102 D. 8 × 104
Mariana [72]

(7.2 × 10^7) ÷ (9 × 10^4)

= (7.2 / 9) x 10^(7 - 4)

= 0.8 x 10^3

= 8 x 10^2

Answer

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5 0
3 years ago
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