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sattari [20]
3 years ago
13

In 6n + 8, n is best described as ___. A a coefficient B a variable C an expression D a term

Mathematics
2 answers:
nikklg [1K]3 years ago
7 0
In 6 n + 8,
n is best described as B ) a variable.
Thank you.
gayaneshka [121]3 years ago
6 0
Variable, because its a letter<span />
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PLEASE HELP!!!!<br><br> Find the value of x.<br> 130 degrees<br> Xdegrees
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Answer:

25

Step-by-step explanation:

130+25+25=180

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A construction worker has a cable that is 8 yards long. He wants to cut it into 9 equal-length pieces. How long will each piece
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A test of H0: p = 0.5 versus Ha: p &gt; 0.5 has the test statistic z = 1.15. Part A: What conclusion can you draw at the 5% sign
Nadya [2.5K]

Answer:

Part A: The null hypothesis failed to be rejected.

Part B: The null hypothesis failed to be rejected.

Step-by-step explanation:

We have an hypothesis test with null and alternative hypothesis H0: p = 0.5 versus Ha: p > 0.5, which has the test statistic z=1.15.

Part A: If the significance level is 0.05, the conclusion depends on the P-value.

If the P-value is below 5%, the null hypothesis is rejected.

The P-value for this right-tailed tes and z=1.15 is:

P-value=P(z>1.15)=0.125

The P-value is bigger than the significance level, so the effect is not significant and the null hypothesis is failed to be rejected.

Part B: In this case, the significance level is 0.01 and, as the alternative hypothesis is defined with an unequal sign, the test is two-tailed.

This changes the way we calculate the P-value, as we need to compute the two tails.

The P-value is:

P-value=2P(z>1.15)=0.25

The P-value is bigger than the significance level, so the effect is not significant and the null hypothesis is failed to be rejected.

5 0
3 years ago
Prove that the statement (ab)^n=a^n * b^n is true using mathematical induction.
mamaluj [8]

Answer:

see below

Step-by-step explanation:

      (ab)^n=a^n * b^n

We need to show that it is true for n=1

assuming that it is true for n = k;

(ab)^n=a^n * b^n

( ab) ^1 = a^1 * b^1

ab = a * b

ab = ab

Then we need to show that it is true for n = ( k+1)

or (ab)^(k+1)=a^( k+1) * b^( k+1)

Starting with

  (ab)^k=a^k * b^k    given

Multiply each side by ab

ab *  (ab)^k= ab *a^k * b^k

   ( ab) ^ ( k+1) = a^ ( k+1) b^ (k+1)

Therefore, the rule is true for every natural number n

5 0
3 years ago
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