Solution :
Given data :
Mass of ice, m = 200 g
Mass of water, M = 500 g
Temperature of ice = 0°C
Temperature of water = 20°C
We known ;
The latent heat of fusion of water is
The specific heat of water, C = 4.18 kJ/kg K
a). Heat required to change the ice into water is :
J
Heat required to cool the warm water is :
From above result,
This means that total ice could not melt.
So, the temperature must be T = 0°C
b). Q' = mL
m = 0.1253 kg
m = 125.3 g
m = 125 g
Therefore, 125 g of ice had melted.
Using Ohm's Law, R = V/I;
R = (1.5V)/(0.5A) = 3.0Ω
A. Parallel and have a good day
The answer requures the application of the knowledge of electrostatics to solve the problem successfully. The solution can be found in the attachment below.
Explanation:
The steel would expand by 4. 8 * 10^-3 cm
<h3>How to determine the linear expansion</h3>
The change in length ΔL is proportional to length L. It is dependent on the temperature, substance, and length.
Using the formula:
ΔL= α LΔT
where ΔL is the change in length L = 10cm
ΔT is the change in temperature = 60° - 20° = 40° C
α is the coefficient of linear expansion = 1.2 x 10^-5 °C
Substitute into the formula
ΔL =
ΔL = cm
Therefore, the steel would expand by 4. 8 * 10^-3 cm
Learn more about linear expansion here:
brainly.com/question/14325928
#SPJ1