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nasty-shy [4]
3 years ago
10

A motorcycle rider moving with an initial velocity of 9.2 m/s uniformly accelerates to a speed of 19.1 m/s in a distance of 32.0

m.
What is the acceleration?
Physics
1 answer:
777dan777 [17]3 years ago
8 0

Answer:

4.38 m/s^2

Explanation:

If,

Initial velocity(u) is 9.2 m/s

Final velocity (v) is 19.1 m/s

Distance moved(s) in that period is 32 m

Therefore we use the formula,

v^2 = u^2 + 2as

; (19.1)^2 = (9.2)^2 + 2(32)a...then move the variables without a to one side..,

; 280.17 = 64a...then divide both sides by 64

; Acceleration = 4.38 m/s^2

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During the last shot of the game, the basketball goes from rest to 15 m/s and reaches the backboard in 0.41 s. What was the acce
Anna [14]

Answer: a= 37m

Explanation: V= 15 m/s (Velocity) t= 0.41s (time) formula: a= v/t

15 m/s / 0.41 (15 divided by 0.41) = 36.583m

There are 2 significant digits, 36, you look at the third digit, either round up or down in this case up to 36. a= 37m

5 0
3 years ago
10. A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant
vladimir1956 [14]
The velocity of the ball is 30.0 m/s.
5 0
3 years ago
At time t1 = 14 s, a car is located at 99, 80, 27 m and has velocity 4, 0, −3 m/s. At time t2 = 18 s, what is the position of th
Korvikt [17]

Answer:

115, 80, 15m

Explanation

t1 = 14s

t2 = 18s

change in time = 4s (18-14)

r(final) = r(initial) + (average velocity) x (change in time)

multiply the average velocity with the change in time

= (4, 0, -3) x 4 = 16, 0, -12

now we'll add this value to the initial position of the car

(99, 80, 27)m + (16, 0, -12)m = (115, 80, 15)m

8 0
3 years ago
Anyone know how to solve this? 4+9×2÷3−1
Nutka1998 [239]

You want to use PEMDAS to solve this equation.

4+9*2/3-1

4+18/6-1

4+6-1

10-1

9

Your answer is 9

Thanks -John

If you have anymore question just ask! :)

5 0
3 years ago
Consider a household that uses 14,000 kWh of electricity and 900 gal of fuel oil, per year, during a heating season. The average
MissTica

Answer:

reduction in the amount of CO₂ emissions by that household per year is 9517.2 lbm per year

Explanation:

given data

electricity consume = 14000 kWh

fuel consume = 900 gal

CO₂ produced of fuel = 26.4 lbm/gal

CO₂ produced of electricity  = 1.54 lbm/kWh

oil and electricity usage = 21 percent

to find out

the reduction in the amount of CO₂ emissions

solution

we calculate the amount of CO₂ produce here that is

amount of CO₂ produce = ( electricity consume×CO₂ produce electricity + fuel consume × CO₂ consume fuel )    ........................1

put here value

amount of CO₂ produce = ( 14000 × 1.54 + 900 × 26.4 )  

amount of CO₂ produce = 45320 lbm/yr

we know reduction is 21%

so

reduction in amount of CO₂ produced is

reduction in CO₂ produced = 45320 × 21%

reduction in CO₂ produced = 9517.2 lbm per year

so reduction in the amount of CO₂ emissions by that household per year is 9517.2 lbm per year

3 0
3 years ago
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