<span> One </span>volt<span> is </span>defined<span> as the difference in electric potential between two points of a conducting wire when an electric current of one ampere dissipates one watt of power between those points.</span>
Answer:
S=2,P=6,D=10,F=14. The total number of electrons contained by s,p,d,f subshells is 32
<span>my first part it like that as we all know that flux density is the charge per unt area here charge is 60uc so divide 60uc by (4*pi*r2) we get D= 7.06*10^-5 c/m2
</span><span>NOW given is portion with r=26cm theta= 0 to pi/2 and phi = 0 to pi/2
calculate required region area with formula =double integral(r^2sintheta dtheta dphi)
we get =.106m^2 now multiply D*Required region we get 7.5uc</span>
Answer:
Upright, Reduced
Explanation:
Given that,
Height of the object, h = 20 cm
Image distance, v = 25 cm
Height of the image, h' = 5 cm
We know that the magnification of the mirror is given by :
u = -100 cm (negative due to sign conventions)
Let f is the focal length of the lens. It can be calculated as :
f = 20 cm
It is seen that the focal length of the lens is positive. So, it is a convex lens. The image formed by the convex lens is Upright, Reduced. Hence, the correct option is (a).
Answer:
The final speed will be "".
Explanation:
The given values are:
Potential difference,
Δv = 400 v
Radius,
r = 0.5580 cm
As we know,
⇒
and,
⇒
then,
⇒
On substituting the values, we get
⇒
⇒
⇒