Answer:
5.9 cm
Explanation:
We'll begin by calculating the spring constant (K) of the spring. This can be obtained as follow:
Force (F) = 15 N
Extention (e) = 3 cm
Spring constant (K) =.?
F = Ke
15 = K × 3
Divide both side by 3
K = 15 / 3
K = 5 N/cm
Therefore, the spring constant (K) is 5 N/cm.
Now, we shall determine how far the spring will stretch when a 3 kg candy is placed on the spring balance.
This can be obtained as follow:
First, we shall determine the weight of the object.
Mass of object = 3 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Weight (W) =?
W = mg
W = 3 × 9.8
W = 29.4 N
Finally, we shall determine how far the spring will stretch as follow:
Weight (W) = Force (F) = 29.4 N
Spring constant (K) = 5 N/cm
Extention (e) =?
F = ke
29.4 = 5 × e
Divide both side by 5
e = 29.4 / 5
e = 5.88 ≈ 5.9 cm
Therefore, the spring will stretch 5.9 cm when a 3 kg candy is placed on the spring balance.
Answer:
Explanation:
a / xy = 2x + a
a = 2x²y + axy
a(1 - xy) = 2x²y
a = 2x²y / (1 - xy)
a / xy = 2x + a
a = 2x²y + axy
a = y(2x² + ax)
y = a / (2x² + ax)
a / xy = 2x + a
a = 2x²y + axy
a / xy = 2x + a
0 = 2yx² + ayx - a
x = (-ay ±√((ay)² - 4(2y)(-a))) / (2(2y))
x = (-ay ±√(a²y² + 8ay)) / 4y
Answer:
R₃ = 4.77 x 10⁻¹⁰ m = 0.477 nm
Explanation:
In 1913, Neil Bohr proposed an atomic model theory, based upon Quantum theory of radiation. This theory described the atomic structure, removing the defects of Rutherford's Model.
In this theory Bohr also derived the formula for the radius of nth orbit of hydrogen atom. The formula is as follows:
Rn = n²(0.53 x 10⁻¹⁰) m
Where,
Rn = Radius of nth orbit of hydrogen atom
n = no. of orbit
Therefore, for 3rd orbit
n = 3
R₃ = (3)²(0.53 x 10⁻¹⁰) m
<u>R₃ = 4.77 x 10⁻¹⁰ m = 0.477 nm</u>
Answer:
2×10^-4m^3/0.002m^3
Explanation:
first know the formula of getting density which is
density=mass/volume
substitute with values given in the problem
{before beginning convert all the values to SI units}
13600m/cm^3=2.27kg/x
calculate to solve for x=volume
As we know that when base react with acid to form salt and water. This type of reaction is known as Neutralization reaction.
When Sodium Hydroxide reacts with Hydrochloric acid to form Sodium Chloride and Water.
As a result of neutralization reaction Sodium Chloride and Water is formed.