Wave speed is always (frequency) x (wavelength)
Speed = (450 /sec) x (0.52 m)
= 234 m/sec .
Answer:
1800 m
Explanation:
This question requires you to calculate the distance traveled after 6 minutes at a speed of 5m/s
Given speed as 5m/s and time is 6 minutes then;
Change minutes to seconds by multiplying the minutes by 60 seconds
1 minute=60 seconds
6 minutes= 6*60 = 360 seconds
Apply the formula for speed where;
S=D/T where S is speed, D is distance and T is time
To get D , rewrite formula as S*T
where S= 5m/s and T=360s
D= 5*360 =1800m
Answer:
The time where the avergae speed equals the instaneous speed is T/2
Explanation:
The velocity of the car is:
v(t) = v0 + at
Where v0 is the initial speed and a is the constant acceleration.
Let's find the average speed. This is given integrating the velocity from 0 to T and dividing by T:

v_ave = v0+a(T/2)
We can esaily note that when <u><em>t=T/2</em></u><u><em> </em></u>
v(T/2)=v_ave
Now we want to know where the car should be, the osition of the car is:

Where x_A is the position of point A. Therefore, the car will be at:
<u><em>x(T/2) = x_A + v_0 (T/2) + (1/8)aT^2</em></u>
Answer:

Explanation:
As given point p is equidistant from both the charges
It must be in the middle of both the charges
Assuming all 3 points lie on the same line
Electric Field due a charge q at a point ,distance r away

Where
- q is the charge
- r is the distance
-
is the permittivity of medium
Let electric field due to charge q be F1 and -q be F2
I is the distance of P from q and also from charge -q
⇒
F1
F2
⇒
F1+F2=
Answer:
a. 1000N/C
Explanation:
Data mentioned in the question
Electrical field magnitude = 1000 NC
Perpendicular distance = 0.1 m
Perpendicular distance = 0.2 m
Based on the above information, the electric field is
As we know that

where,
= surface charge density
E = distance from nearby point to sheet i.e be independent
The distance at 0.1 and 0.2, the electric field would remain the same
So,
Based on the above explanation, the first option is correct