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borishaifa [10]

2 years ago

6

A piece of steel expands 10 cm when ur is heated from 20 to 50 degrees Celsius. How much would it expand if it was heated from 2

0 to 60 degrees Celsius

1 answer:

faltersainse [42]2 years ago

8 0

The steel would expand by 4. 8 * 10^-3 cm

<h3>How to determine the linear expansion</h3>

The change in length ΔL is proportional to length L. It is dependent on the temperature, substance, and length.

Using the formula:

ΔL= α LΔT

where ΔL is the change in length L = 10cm

ΔT is the change in temperature = 60° - 20° = 40° C

α is the coefficient of linear expansion = 1.2 x 10^-5 °C

Substitute into the formula

ΔL = $1.2 * 10^-5 * 10 * 40$

ΔL = $4.8 * 10 ^-3$ cm

Therefore, the steel would expand by 4. 8 * 10^-3 cm

Learn more about linear expansion here:

brainly.com/question/14325928

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lianna [129]

Japanese Honeysuckle

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3 years ago

In the writing of ionic chemical formulas, what factor is "crossed over" in the crossover rule?

Aleks04 [339]

In the writing of ionic chemical formulas the value of each ion's charge is crossed over in the crossover rule.

Rules for naming Ionic compounds

Frist Rule
The cation (element with a negative charge) is written first in the name then the anion(element with a positive charge) is written second in the name.
Second rule
When the formula unit contains two or more of the same polyatomic ion, that ion is written in parentheses with the subscript written outside the parentheses.
Example: Sodium carbonate is written as Na₂CO₃ not Na₂(CO)₃
Third rule
If the cation is a metal ion with a fixed charge then the name of the cation will remain the same as the (neutral) element from which it is derived (Example: Na+ will be sodium).
If the cation is a metal ion with a variable charge, the charge on the cation is indicated using a Roman numeral, in parentheses, immediately following the name of the cation (example: Fe³⁺ = iron(III)).

Fourth rule
If the anion is a monatomic ion, the anion is named by adding the suffix <em>-ide</em> to the root of the element name (example: F = Fluoride).

The oxidation state of each ion is also important, thus in the crossover rule, the value of each ion's charge is crossed over.

Learn more about chemical formulas here:

<u>brainly.com/question/11995171</u>

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3 0

2 years ago

Bill drives west at 20\, \dfrac{\text m}{\text s}20 s m 20, start fraction, start text, m, end text, divided by, start text, s

vovangra [49]

Answer:

Positive Horizontal line, constant

Explanation:

4 0

3 years ago

Read 2 more answers

Based on the following equation, answer the questions below. ρ = (2γϕ + ψ)/rg where ρ [=] moles per cubic foot [mol/ft3] γ [=] j

AlekseyPX

1) Fundamental units of $\Psi$ are $[\frac{mol}{m\cdot s^2}]$

2) Fundamental units of $\Phi$ are $[\frac{mol}{m^3}]$

Explanation:

The equation for the variable $\rho$ is

$\rho =\frac{2\gamma \Phi+\Psi}{rg}$

where we have:

$\rho$ measured in $[\frac{mol}{ft^3}]$

$\gamma$ measured in $[\frac{J}{kg}]$

$r$ measured in $[in]$

$g$ measured in $[\frac{m}{s^2}]$

We can re-write the equation as

$\rho rg = 2\gamma \Phi + \Psi$

And we notice that the units of the term on the left must be equal to the units of the term on the right.

This means that:

1) First of all, $\Psi$ must have the same units of $\rho r g$ . So,

$[\rho r g]=[\frac{mol}{ft^3}][in][\frac{m}{s^2}]$

However, both ft (feet) and in (inches) are not fundamental dimensions: this means that they can be expressed as meters. Therefore, the fundamental units of $\Psi$ are

$[\Psi]=[\frac{mol}{m^3}][m][\frac{m}{s^2}]=[\frac{mol}{m\cdot s^2}]$

2)

The term $2\gamma \Phi$ must have the same units of $\Psi$ in order to be added to it. Therefore,

$[\gamma \Phi] = [\frac{mol}{m\cdot s^2}]$

We also know that the units of $\gamma$ are $[\frac{J}{kg}]$ , therefore

$[\frac{J}{kg}][\Phi]= [\frac{mol}{m\cdot s^2}]$

And so, the fundamental units of $\Phi$ are

$[\Phi]= [\frac{mol\cdot kg}{J\cdot m\cdot s^2}]$

However, the Joules can be written as

$[J]=[kg][\frac{m^2}{s^2}]$

Therefore

$[\Phi]= [\frac{mol\cdot kg}{(kg \frac{m^2}{s^2})\cdot m\cdot s^2}]=[\Phi]= [\frac{mol}{m^3}]$

#LearnwithBrainly

7 0

3 years ago

A 25.0 kg object moving at +15.0 m/s strikes a 15.0 kg

lesya692 [45]

The final velocity of the 15 kg mass is 18.33 m/s.

<h3>Conservation of linear momentum</h3>

The final velocity of the 15 kg mass can be determined by applying the principles of conservation of linear momentum as follows;

$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\\\\$

Where;

m₁ is the mass of the first object = 25 kg
u₁ is the initial velocity of the first object = 15 m/s
m₂ is the mass of the second object = 15 kg
u₂ is the initial velocity of the second object = -10 m/s
v₁ is the final velocity of the first object = -2 m/s
v₂ is the final velocity of the second object

Thus, the final velocity of the 15 kg mass after the collision is 18.33 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

8 0

2 years ago