Answer:
R = 28.125 ohms
Explanation:
Given that,
The voltage of a bulb, V = 4.5 V
Current, I = 0.16 A
We need to find the resistance of the filament. Using Ohm's law,
V = IR
Where
R is the resistance of the filament
So,

So, the resistance of the filament is equal to 28.125 ohms.
Answer and Explanation:
Polar molecules are formed as a result of unequal sharing of electrons by the atoms in the molecule which creates polarization like that in water molecule.
If the electrons are shared equally by the atoms in the molecule then there won't be any polarization of the molecule and the molecule is non polar.
Electro-negativity is that property of an atom which lets it attract negative charges, i.e., electrons. The more the electro-negativity of an atom in the molecule the more are the chances of its polarization.
Answer:
A. Their same forces repel each other, and their opposite forces attract each other.
Explanation:
As we know by the property of electric charge that similar charges repel each other and opposite charges attracts each other
So here we have similar situation in magnets also
Two similar poles or like poles of magnet i.e. North - North poles or South - South poles always repel each other
And also we can see that opposite poles of magnet each other i.e. North pole and south pole always attract each other.
SO here correct answer is
A. Their same forces repel each other, and their opposite forces attract each other.
Answer:
In a coiled spring, the particles of the medium vibrate to and fro about their mean positions at an angle of
A. 0° to the direction of propagation of wave
Explanation:
The waveform of a coiled spring is a longitudinal wave, which is made up of vibrations of the spring which are in the same direction as the direction of the wave's advancement
As the coiled spring experiences a compression force and is then released, it experiences a sequential movement of the wave of the compression that extends the length of the coiled spring which is then followed by a stretched section of the coiled spring in a repeatedly such that the direction of vibration of particles of the coiled is parallel to direction of motion of the wave
From which we have that the angle between the direction of vibration of the particles of the coiled spring and the direction of propagation of the wave is 0°.