Which sediment size would allow water to flow through at the fastest rate?
1 answer:
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Answer : The cell emf for this cell is 0.077 V
Solution :
The balanced cell reaction will be,
Oxidation half reaction (anode):
Reduction half reaction (cathode):
In this case, the cathode and anode both are same. So, is equal to zero.
Now we have to calculate the cell emf.
Using Nernest equation :
where,
n = number of electrons in oxidation-reduction reaction = 2
= ?
= 0.0111 M
= 4.50 M
Now put all the given values in the above equation, we get:
Therefore, the cell emf for this cell is 0.077 V