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3 years ago

Which sediment size would allow water to flow through at the fastest rate?

1 answer:

4 0

The sediment size that would allow water to flow through at the fastest rate are pebbles. Sediment is a naturally occurring material that is broken down by processes of weathering and erosion, and is consequently transported by the action of wind, or ice, and or by the force of gravity acting on the particles. Pebble is a clast of rock with a particle size of 2 to 64 millimeters based on the scale of sedimentology.

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Which lists types of materials from most conductive to least conductive?

Lilit [14]

Superconductor, conductor, semiconductor, insulator

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3 years ago

Read 2 more answers

Help! I don’t really know what it’s asking

Misha Larkins [42]

You have to do the math of each and see which one adds up to 66.5

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2 years ago

Which of the following provides evidence that there must be at least two types of electrical charge, but that there is only one

polet [3.4K]

Answer:

Option D (On the...............dominate) would be the right approach.

Explanation:

The Gravitational constant (G) will be:

= $6.67\times 10^{-11}$

The Coulomb's law constant (K) will be:

= $9\times 10^9$

Throughout particular, these have been determined that among 2 substances with almost the similar form of charge, the combination of electromagnetic as well as the force does seem to be usually the following:

⇒ $\frac{f_e}{f_g}\sim 10^{42}$

By that same argument, the electrostatic force including its planet's atmosphere would have strongly influenced the effect, as well as maybe the planet's atmosphere, would have crashed, or perhaps the earth would have shifted at a much longer exposure from one another and.
Throughout particular, astronomical distance statutory framework that gravity seems to be predominant, whereas electrostatic forces have been generally ignored. It is quite since there are so many categories of allegations throughout the planet's atmosphere that balance out someone else's effects, there's only yet another form of momentum, because although the forces are still cumulative, as well as therefore offering to help everything hold to the universe, encouraging the universe just to rotate across the sun.

The latter three choices aren't connected to either the situation mentioned in the clarification segment elsewhere here.

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3 years ago

In the graph below, why does the graph stop increasing after 30 seconds?

stepladder [879]

Answer:

The answer is "Option C".

Explanation:

It's evident from the figure below that after thirty minutes, not no more hydrogen can be created because all of the reactants have converted into products.

hydrogen gas created in cm cubes per period x = 20 seconds, y = 45 centimeters squared, and so on.

A reaction's terminus (the graph's flat line) indicates that no further products are being created during the reaction.

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2 years ago

A bolt is dropped from a bridge under construction, falling 96 m to the valley below the bridge. (a) How much time does it take

irakobra [83]

Answer:

a)It takes the bolt 0.25 s to pass the last 11% of the fall.

b)When the bolt begins to fall the last 11% of the fall its velocity is -41.2 m/s.

c)The velocity of the bolt just before it reaches the ground is -43.6 m/s

Explanation:

Hi there!

a) Let´s calculate how much distance it is the last 11% of the fall:

96 m · 0.11 = 10.56 m

So, we have to find how much time it takes the bolt to pass from a height of 10.56 m to the ground.

First, let´s calculate how much time it takes the bolt to reach a height of 10.56 m. For that we can use this equation:

h = h0 + v0 · t + 1/2 · g · t²

Where:

h = height of the bolt at a time t.

h0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity.

If we consider the ground as the origin of the frame of reference, then h0 = 96 m. Since the bolt is dropped, the initial velocity is zero (v0 = 0). Then, the equation gets reduce to this:

h = h0 + 1/2 · g · t²

We have to find at which time h = 10.56 m.

10.56 m = 96 m - 1/2 · 9.8 m/s² · t²

Solving for t:

√(-2 · (10.56 m - 96 m) / 9.8 m/s²) = t

t = 4.2 s

Now that we have the time at which the bolt is located at 10.56 m above the ground, we can calculate the velocity of the bolt at that time.

The equation of velocity (v) of the bolt is the following:

v = v0 + g · t

at t = 4.2 s.

v = 0 - 9.8 m/s² · 4.2 s

v = -41.2 m/s

When the bolt begins to fall the last 11% of the fall its velocity is -41.2 m/s.

Now, we can calculate how much time it takes to fall the last 10.56 m.

The initial velocity of the bolt will be the velocity at h = 10.56 m. The initial height will be 10.56 m.

h = h0 + v0 · t + 1/2 · g · t²

We have to find the time at which h = 0 (the bolt hits the ground)

0 = 10.56 m - 41.2 m/s · t - 1/2 · 9.8 m/s² · t²

Solving the quadratic equation using the quadratic formula:

t = 0.25 s (the other solution of the quadratic equation is negative and thus discarded).

It takes the bolt 0.25 s to pass the last 11% of the fall.

Now, let´s calculate the velocity of the bolt when it reaches the ground:

v = v0 + g · t

v = -41.2 m/s - 9.8 m/s² · 0.25 s

v = -43.6 m/s

The velocity of the bolt just before it reaches the bolt is -43.6 m/s

6 0

3 years ago