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MariettaO [177]
3 years ago
8

When the direction of acceleration is opposite to the direction of velocity

Physics
2 answers:
wariber [46]3 years ago
7 0

Answer:

yes this is truly the wrong answer

nadezda [96]3 years ago
4 0

Answer:

If acceleration points in the same direction as the velocity, the object will be speeding up. And if the acceleration points in the opposite direction of the velocity, the object will be slowing down.

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Multiply the following numbers, using scientific notation and the correct amount of significant digits. 1.003 m⋅3.09 =
Blababa [14]

The correct answer to the question is: 3.10

CALCULATION:

As per the question, the two numbers are given as 1.003 and 3.09.

We are asked to multiply these two numbers.

The multiplication result of the two numbers = 1.003 × 3.09

= 3.09927.

We have to rewrite this result in terms of rule of significant digits.

The total number of significant digits of first number is 4.

The total number of significant digits of second number is 3.

Hence, the minimum number of significant digits is 3.

As per the significant rules for multiplication, the final result will follow the minimum number of significant digits.

Hence, the final answer should contain only three significant digits.

The multiplication result is rounded off after three significant digits.

The fourth significant digit is 9 which is to be rounded off.

As, it is greater than 5, so 1 will be added to the preceding digit.

Hence, the multipled result = 3.10



Hence, the correct answer of this question is 3.10





5 0
3 years ago
Read 2 more answers
What is the mass of an object travelling at 25 m/s with a kinetic energy of 3775 J?
Arte-miy333 [17]

Answer:

<h2>You can do 6516-3775=2741</h2><h2 /><h2>The difference is 27141 kilometers</h2><h2 /><h2>Did this help?</h2><h2>⇒  Yes or No?</h2>
4 0
3 years ago
PLEASEEE HELP ME WITH THIS ALSO. I DONT WANT TO FAIL. You push a merry-go-round on which Kim and Katie are riding. Kim weighs 45
Serjik [45]

Answer:

The body weight

Explanation:

5 0
3 years ago
If only an external force can change the velocity of a body, how can the internal force of the brakes bring a car to rest? 1. It
RoseWind [281]

Answer:

4. It is the force of the road on the tires (an external force) that stops the car.

Explanation:

If there is no friction between the road and the tires, the car won't stop.

You can see this, for example, when there is ice on the road. You can still apply the brakes (internal force), but since there is no friction (external force) the car won't stop.

The force of the brakes on the wheels is not what makes the car stop, it is the friction of the road against still tires that makes it stop.

3 0
3 years ago
a race car accelerates uniformly from 18.5 m/s to 46.1m/s in 2.47 seconds detrrmine the acceleration of the car and distance tra
LenaWriter [7]

Because acceleration is constant, the acceleration of the car at any time is the same as its average acceleration over the duration. So

a=\dfrac{\Delta v}{\Delta t}=\dfrac{46.1\,\frac{\mathrm m}{\mathrm s}-18.5\,\frac{\mathrm m}{\mathrm s}}{2.47\,\mathrm s}=11.2\,\dfrac{\mathrm m}{\mathrm s^2}

Now, we have that

{v_f}^2-{v_0}^2=2a\Delta x

so we end up with a distance traveled of

\left(46.1\,\dfrac{\mathrm m}{\mathrm s}\right)^2-\left(18.5\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(11.2\,\dfrac{\mathrm m}{\mathrm s^2}\right)\Delta x

\implies\Delta x=79.6\,\mathrm m

6 0
3 years ago
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