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MariettaO [177]
3 years ago
8

When the direction of acceleration is opposite to the direction of velocity

Physics
2 answers:
wariber [46]3 years ago
7 0

Answer:

yes this is truly the wrong answer

nadezda [96]3 years ago
4 0

Answer:

If acceleration points in the same direction as the velocity, the object will be speeding up. And if the acceleration points in the opposite direction of the velocity, the object will be slowing down.

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A 700kg car had 12,000 joules of kinetic energy, Calculate it’s velocity !! please help due right now !!
Margarita [4]

Answer:

velocity of car=5.855 m/s

Explanation:

8 0
3 years ago
Se lanza una piedra de 3.00 N verticalmente hacia arriba desde el suelo. Se observa que, cuando está 15.0 m sobre el suelo, viaj
BARSIC [14]

Answer:

(a). The speed at the moment of being thrown is 30.41 m/s.

(b). The maximum height is 47.18 m.

Explanation:

Given that,

Weight of stone = 3.00 N

Height = 15 m

Speed = 25.0 m/s

(a). We need to calculate the speed at the moment of being thrown

Using work energy theorem

W=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)

-mg\times d=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)

Put the value into the formula

-9.8\times15=\dfrac{1}{2}\times(v_{2}^2-v_{1}^2)

-2\times9.8\times15=25^2-v_{1}^2

-v_{1}^2=-300-25^2

v_{1}=\sqrt{925}

v_{1}=30.41\ m/s

(b). We need to calculate the maximum height

Using work energy theorem

[tex]W=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2

mg\times d=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2

Here, \dfrac{1}{2}mv_{2}^2=0

-(mg)\times d=\dfrac{1}{2}mv_{1}^2

d=\dfrac{v_{1}^2}{2g}

Put the value into the formula

d=\dfrac{30.41^2}{2\times9.8}

d=47.18\ m

Hence, (a). The speed at the moment of being thrown is 30.41 m/s.

(b). The maximum height is 47.18 m.

6 0
2 years ago
Physicists and engineers from around the world came together to build the largest accelerator in the world, the Large Hadron Col
Vsevolod [243]

Answer:

Explanation:

From the question,

The kinetic energy of protons

K = 7eV.

Mass of proton and the speed of light are the given parameters.

Please kindly go through the files I attached for a step by step explanation of the answer required.

5 0
3 years ago
A rock with a mass of 540 g in air is found to have an apparent mass of 342 g when submerged in water. (a) What mass of water is
AleksandrR [38]

(a) 198 g

When the rock is submerged into the water, there are two forces acting on the rock:

- its weight, equal to W=mg (m=mass, g=acceleration of gravity), downward

- the buoyant force, equal to B=m_w g (m_w=mass of water displaced), upward

So the resultant force, which is the apparent weight of the rock (W'), is

W'=W-B

which can be rewritten as

m'g = mg-m_w g

where m' is the apparent mass of the rock. Using:

m = 540 g

m' = 342 g

we find the mass of water displaced

m_w = m-m'=540 g-342 g=198 g

(b) 1.98\cdot 10^{-4} m^3

If the rock is completely submerged, the volume of the rock corresponds to the volume of water  displaced.

The volume of water displaced is given by

V_w = \frac{m_w}{\rho_w}

where

m_w = 198 g = 0.198 kg is the mass of the water displaced

\rho_w = 1000 kg/m^3 is the density of the water

Substituting,

V_w = \frac{0.198}{1000}=1.98\cdot 10^{-4} m^3

And so this is also the volume of the rock.

(c) 2727 kg/m^3

The average density of the rock is given by

\rho = \frac{m}{V}

where

m = 540 g = 0.540 kg is the mass of the rock

V=1.98\cdot 10^{-4} m^3 is its volume

Substituting into the equation, we find

\rho = \frac{0.540 kg}{1.98\cdot 10^{-4}}=2727 kg/m^3

3 0
3 years ago
Question 2: In 2-4 sentences, explain what would happen to the cell if the nucleus didn’t work?
VladimirAG [237]

Answer:

Then the cell won't be able to function properly. With no nucleus the cell will lose control. It won't know what to do and there will be no cell division.

Explanation:

7 0
2 years ago
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