Answer:
Pretty sure 25%.
Step-by-step explanation:
First, you would need to see how many times 60 goes into 100, because a percent is ALWAYS over 100. You should get an answer of 1.66666667. Then you if you multiply it to one of the numbers then you have to do it to the other number. So, you would do 15 times 1.66666667. You would get 25. So, that would be 25 over 100 or 25/100. And 25 over 100 is 25%.
I hope I helped! :) Sorry if it's wrong :(
The answer is B. Fabiana has completed the same amount of the course as Samantha because 6/15=8/20. Both fractions reduce to 2/5. Therefore, they are equivalent.
Answer:
10
Step-by-step explanation:
10-7 do it yourself and don't vheat
Answer:
91.02% probability of selling more than 4 properties in one week.
Step-by-step explanation:
For each property, there are only two possible outcomes. Either it is sold, or it is not. The chance of selling any one property is independent of selling another property. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem we have that:

Compute the probability of selling more than 4 properties in one week.
Either you sell 4 or less properties in one week, or you sell more. The sum of the probabilities of these events is decimal 1. So

We want to find
. So

In which

So






So

Finally

91.02% probability of selling more than 4 properties in one week.
Answer:
one solution
Step-by-step explanation:
A system of linear equations usually has a single solution, but sometimes it can have no solution (parallel lines) or infinite solutions (same line). This article reviews all three cases. One solution. A system of linear equations has one solution when the graphs intersect at a point.