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MariettaO [177]
3 years ago
14

Ace Truck leases its 10-ft box truck at $30/day and $0.50/mi, whereas Acme Truck leases a similar truck at $25/day and $0.55/mi.

Mathematics
1 answer:
scoray [572]3 years ago
8 0

Answer:

Ace Truck

C(m) = 30 + 0.5*m

Acme Truck

C(m) = 25 + 0.55*m

Step-by-step explanation:

The cost function to lease a box truck from a company has the following format:

C(m) = F + a*m

In which F is the fixed cost and a is the cost per mile m.

(a) Find the daily cost of leasing from each company as a function of the number of miles driven.

Ace Truck

$30/day and $0.50/mi. This means that F = 30, a = 0.50. So

C(m) = 30 + 0.5*m

Acme Truck

$25/day and $0.55/mi. This means that F = 25 a = 0.55. So

C(m) = 25 + 0.55*m

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Answer:

slope=3,y-intercept=6

Step-by-step explanation:

Slope is the rate of change so It is an independent variable and has an x at the end

The y-intercept is the initial value which is technically the start off and the number 6 seems to be a dependent variable.

7 0
3 years ago
Which simplified fraction is equal to 0.53?
liq [111]

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53/100

Step-by-step explanation:

5 0
3 years ago
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In a sample of 679 new websites registered on the Internet, 42 were anonymous (i.e., they shielded their name and contact inform
Semmy [17]

Answer:

95% Confidence interval:  (0.0429,0.0791)      

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 679

Number of anonymous websites, x = 42

\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

Putting the values, we get:

0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)

is the required confidence interval for proportion of all new websites that were anonymous.

8 0
3 years ago
4 + x/ 7 = 2 plz answer
irakobra [83]

4+ x/7 = 2

x/7=2 -4

x = 7(2-4)

x= -14

7 0
3 years ago
Read 2 more answers
Help me please<br><img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20ln%28x%20%7B%20%7D%20%5E%7B2%7D%20%2B%202%20%29%20" id="
CaHeK987 [17]
➡Answer: x=√(e^y-2)

❇Explanation:
Step1: Let f(x)=y,then

↪y=ln(x²+2)

Step2: Converting it into exponential form,

↪e^y=x²+2

↪x²=e^y-2

Step3: Taking square root of both sides,

↪x=√(e^y-2)

❇Note:

ln means log with base e.

So in step 2 , base e of ln (x²+2) goes to other side in the form e^y. That is simply the property of log I used there..

Hope this helps!
3 0
3 years ago
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