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MariettaO [177]
3 years ago
14

Ace Truck leases its 10-ft box truck at $30/day and $0.50/mi, whereas Acme Truck leases a similar truck at $25/day and $0.55/mi.

Mathematics
1 answer:
scoray [572]3 years ago
8 0

Answer:

Ace Truck

C(m) = 30 + 0.5*m

Acme Truck

C(m) = 25 + 0.55*m

Step-by-step explanation:

The cost function to lease a box truck from a company has the following format:

C(m) = F + a*m

In which F is the fixed cost and a is the cost per mile m.

(a) Find the daily cost of leasing from each company as a function of the number of miles driven.

Ace Truck

$30/day and $0.50/mi. This means that F = 30, a = 0.50. So

C(m) = 30 + 0.5*m

Acme Truck

$25/day and $0.55/mi. This means that F = 25 a = 0.55. So

C(m) = 25 + 0.55*m

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Please help due today!
fomenos

Answer:

FEG = 67

Step-by-step explanation:

DEG = DEF + FEG

labeling FEG as x to make it simpler while calculating the answer

115 = 48 + x

115 - 48 = 48 - 48 + x

67 = 0 + x

67 = x

67 = FEG

8 0
3 years ago
I rlly need some help please if ur big brains im going to be asking multiple questions right now
Lynna [10]

You can break the shape up into a rectangle and a right triangle.

Use your trig ratios to find the missing sides.

Add all the sides up and you have your perimeter!

//

p = 2(l) + 2(w)

p = 2(10)  + 2(4)

p = 28

//

tan =  \frac{opp}{adj}

\tan(45) =  \frac{10}{adj}

adj =  \frac{10}{ \tan(45) }

adj = 10

{a}^{2}  +  {b}^{2}  =  {c}^{2}

{10}^{2}  + 10 {}^{2}  =  {200}^{2}

\sqrt{200} = 14.14213562

//

p = 10 + 4 + (4 + 10) + 14.14213562

<em>*notice how one of the 10 is left out because it is inside the shape so we can't use that to find perimeter.</em>

p = 42.14

3 0
3 years ago
What is -3.8 as a fraction in simplest form
Paul [167]
-3.8 is -3 8/10 which is -3 4/5 simplified
5 0
3 years ago
Read 2 more answers
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



5 0
3 years ago
Read 2 more answers
Pls can u help me this is due now T-T
Artist 52 [7]

Answer:

SOLUTION: X=5

Step-by-step explanation:

x=5

y=27

vertical input= (0, 1/9)

Hope that helps!

5 0
3 years ago
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