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sergiy2304 [10]

3 years ago

15

On a scale drawing, the scale factor is 1/12. A plum tree is 7 inches tall on the scale drawing. What is the actual height of th

e tree?

1 answer:

elena-s [515]3 years ago

5 0

84 units tall. If one inch is 12 units then seven inches is 84 units.

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If cos θ > 0 and tan θ > 0, which of the following statements MUST be true? (5 points)

solniwko [45]

Yo sup??

cosx>0 in the 1st and 4th quadrant.

tanx>0 in the 1st and 3rd quadrant.

therefore the common solution is x lies in 1st quadrant.

Hence the correct answer is option A.

Hope this helps

5 0

3 years ago

What’s the answer to the top question and steps how to solve?

Leviafan [203]

Answer:

-3.69

Step-by-step explanation:

Exponential equations can be solved by taking Ln (natural logarithm) of both sides. The rule we need to know is:

$Ln(a^b)=bLn(a)$

Now lets work out this problem:

$16^{2x+3}=13^{x-1}\\Ln(16^{2x+3})=Ln(13^{x-1})\\(2x+3)Ln(16)=(x-1)Ln(13)$

Using calculator, we take the values of Ln 16 and Ln 13 as:

Ln 16 = 2.7726

Ln 13 = 2.5649

Now, we can solve for x:

$(2x+3)Ln(16)=(x-1)Ln(13)\\(2x+3)2.7726=(x-1)2.5649\\5.5452x+8.3178=2.5649x-2.5649\\2.9803x=-10.8827\\x=-3.69$

x is -3.69 (rounded to 2 decimal places)

3 0

3 years ago

What is 20b -2 + 34?

DaniilM [7]

Answer:

Dos mas treinta y cuatro da resultado a treinta y seis

Step-by-step explanation:

5+5=10

10+10=20

10+20=30

2+2=4

20+10+4+2=36

7 0

2 years ago

23 degrees 20’48 is the same as _degrees.

allochka39001 [22]

Answer:

$\large\boxed{23^o20'48''=\left(23\dfrac{26}{75}\right)^o}$

Step-by-step explanation:

$\text{We know:}\\\\1^o=60'\to1'=\left(\dfrac{1}{60}\right)^o\\\\1'=60''\to1^o=(60)(60'')=3600''\to1''=\left(\dfrac{1}{3600}\right)^o\\\\23^o20'48''\\\\20'=\left(\dfrac{20}{60}\right)^o=\left(\dfrac{1}{3}\right)^o\\\\48''=\left(\dfrac{48}{3600}\right)^o=\left(\dfrac{1}{75}\right)^o\\\\\text{Therefore}\\\\23^o20'48''=23^o+20'+48''=23^o+\left(\dfrac{1}{3}\right)^o+\left(\dfrac{1}{75}\right)^o\\\\=\left(23+\dfrac{1\cdot25}{3\cdot75}+\dfrac{1}{75}\right)^o=\left(23+\dfrac{25}{75}+\dfrac{1}{75}\right)^o=\left(23\dfrac{26}{75}\right)^o$

4 0

3 years ago

Determine whether the relation is or is not a function.

soldier1979 [14.2K]

Answer:

Not a function because it does not pass the Vertical Line Test.

5 0

2 years ago