Question

The width of a rectangle is 6 less than the length. A second rectangle with perimeter 54, is 3 wider and 2 shorter than the first. Find dimensions of each rectangle.​

Answer 1

Check the picture below.

$\stackrel{\textit{\large 1st rectangle}}{\stackrel{L}{16}\times\stackrel{L-6}{10}}\qquad \qquad \stackrel{\textit{\large 2nd rectangle}}{\stackrel{L-2}{14}\times\stackrel{(L-6)+3}{13}}$