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True [87]
3 years ago
13

What is the y-intercept of the line given by the equation below ? Y=8x + 7

Mathematics
1 answer:
docker41 [41]3 years ago
5 0
The answer is B (0,7)
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(10 + 3x) = 5x<br> Solve please
yanalaym [24]

Answer:

x=5

Step-by-step explanation:

10 +3x = 5x

Subtract 3x from each side

10+3x-3x= 5x-3x

10 =2x

Divide each side by 2

10/2 = 2x/2

5 =x

8 0
3 years ago
Which is the graph of the linear inequality {x – 2y&gt; 6?<br> 1<br> 4 db<br> to to to the<br> O
makvit [3.9K]

This is what I think your looking for

7 0
2 years ago
For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe
Rus_ich [418]

To solve the inequality \frac{x^2+x+3}{2x^2+x-6}\ge \:0

\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:

The numerator x^2+x+3 is not factorizable.

so factor the denominator 2x^2+x-6:

2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\

Now take \mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)

Then we get factor of the denominator as \left(2x-3\right)\left(x+2\right)

Thus \frac{x^2+x+3}{2x^2+x-6}=\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}

Now \mathrm{Compute\:the\:signs\:of\:the\:factors\:of\:}\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}\\

Signs of x^2+x+3>0

\mathrm{Choosing\:ranges\:that\:satisfy\:the\:required\:condition:}\:\ge \:\:0

x\frac{3}{2} is the required solution of the given inequality.

5 0
3 years ago
Read 2 more answers
Is 7- y=5x+11 a standard form
koban [17]

Answer:

No.

Step-by-step explanation:

Because standard form is ax+by=c.

6 0
3 years ago
Zach has $50 to spend on a sweater. Let c represent the cost of the sweater. He has a coupon for 5% off. The expression 50 -(c -
Norma-Jean [14]

Answer:

B and D

Step-by-step explanation:

8 0
3 years ago
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