How many liters of methane gas (CH4) need to be combusted to produce 8.5 liters of water vapor, if all measurements are taken at

Question

4 years ago

11

the same temperature and pressure? Show all of the work used to solve this problem. CH4 (g) + 2O2 (g) CO2 (g) + 2H2O (g)

1 answer:

Ber [7] · Answer 1 · 2022-01-30T10:12:01+03:00

Ber [7]4 years ago

6 0

1 mole of CH4 results to 2 moles of H2O.

If 8.5 liters are to be produced, then (1CH4/2H20)*(8.5L h2o) = 4.25L CH4