Answer:
H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)
Explanation:
H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq) + SO²⁻₄(aq) + H₂O(l)
A careful observation of the equation above, shows that the equation is already balanced.
To obtain the net ionic equation, we simply cancel Mg²⁺ from both side of the equation as shown below:
H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)
Answer: sharing
Reason: They do this to gain stability. The reason they don’t actually transfer is because the difference in electronegativity values are above a certain value.
Answer : The expression for reaction quotient will be :
(1) ![Q_c=\frac{[SO_2][HF]^4}{[SF_4]}](https://tex.z-dn.net/?f=Q_c%3D%5Cfrac%7B%5BSO_2%5D%5BHF%5D%5E4%7D%7B%5BSF_4%5D%7D)
(2) ![Q_c=\frac{[O_2]^2[Xe]}{[XeF_2]}](https://tex.z-dn.net/?f=Q_c%3D%5Cfrac%7B%5BO_2%5D%5E2%5BXe%5D%7D%7B%5BXeF_2%5D%7D)
Explanation :
Reaction quotient 
: It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
(1) The given balanced chemical reaction is,
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted. So, the expression for reaction quotient will be :
(2) The given balanced chemical reaction is,
![2MoO_2(s)+XeF_2(g)\rightarrow 2MoF(l)+Xe(g)+2O_2(g)[/texIn this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted. So, the expression for reaction quotient will be :[tex]Q_c=\frac{[O_2]^2[Xe]}{[XeF_2]}](https://tex.z-dn.net/?f=2MoO_2%28s%29%2BXeF_2%28g%29%5Crightarrow%202MoF%28l%29%2BXe%28g%29%2B2O_2%28g%29%5B%2Ftex%3C%2Fp%3E%3Cp%3EIn%20this%20expression%2C%20only%20gaseous%20or%20aqueous%20states%20are%20includes%20and%20pure%20liquid%20or%20solid%20states%20are%20omitted.%20%20So%2C%20the%20expression%20for%20reaction%20quotient%20will%20be%20%3A%3C%2Fp%3E%3Cp%3E%5Btex%5DQ_c%3D%5Cfrac%7B%5BO_2%5D%5E2%5BXe%5D%7D%7B%5BXeF_2%5D%7D)
Answer;
= 64561.95 g/mole
Explanation;
mass of Fe in 100g = .346g
= .346 / 55.8452 moles
= 0.0061957 moles
These represent 4 moles of Fe in the molecule so moles of hemaglobin
= 0.0061957/4
= 0.0015489 moles
these are in 100 g so mass of 1 mole = 100 / 0.0015489
= 64561.95 g / mole
molar mass of hemoglobin = 64561.95 g/mole
