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Tamiku [17]
4 years ago
8

How to do you not fall in love with someone?

Chemistry
2 answers:
Masteriza [31]4 years ago
7 0
Try not to be in contact with them so much and do things that you love to do that don’t remind you of that person ‍♀️
spin [16.1K]4 years ago
4 0

Answer:

Self value and rational thinking.

Explanation:

If you don't want to fall in love with someone, list reasons as to why. Understand you're amazing and that you don't <em>need</em> to be with anyone. Self value is very important so you don't fall for people that you believe will support you better than you can.

Good luck! :]

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xavier, yaozhou and zara had some beads. xavier and yaozhou had total of 438 beads. xavier and zara had total of 204 beads. youz
SVEN [57.7K]
To solve this problem, we need to set-up algebraic expression. First, use variables to represent the number of beads. 

Let: x = number of Xavier's beads
       y = number of Y<span>aozhou's beads
       z = number of Zara's beads

</span>It is important to note that since we have three unknowns, we should also have three independent equations. <span>Based on the given statements, we have the following three equations:

(1) x + y = 438
(2) x + z = 204
(3) y = 3z

Substitute y in terms of z in equation (1). Then multiply equation (2) with -1. 

x + 3z = 438
-(x + z = 204)
-------------------
      2z = 234
        z = 117

From equation (3),

y = 3(117) = 351

Using equation (1),

x = 438 - 351 = 87

Thus, Xavier had 87 beads.</span>
5 0
3 years ago
If 20. 3 grams of an aqueous solution of iron(ii) chloride, fecl2, contains 2. 71 grams of iron(ii) chloride, what is the percen
Hatshy [7]

If 20. 3 grams of an aqueous solution of iron(ii) chloride contains 2. 71 grams of iron(ii) chloride, then percentage by mass of  iron(ii) chloride in the solution is 13.34%

Calculation,

Given:

mass of an aqueous solution of iron(ii) chloride = 20. 3 grams

mass of iron(ii) chloride = 2. 71 grams

The percentage by Mass is equal to percentage of mass of solute present in total mass of solution. It is also known as Mass percentage.

percentage by Mass = 100× 2. 71 grams/20. 3 grams = 13.34%

Hence, the percentage by mass of  iron(ii) chloride in the solution is 13.34% .

to learn more about mass percentage

brainly.com/question/27108588

#SPJ4

7 0
2 years ago
What isotope remains after the alpha decau of uranium-238?
lbvjy [14]
After alpha decay (234,90) remain from it
4 0
3 years ago
Properties of metals
Nitella [24]

Answer:

Physical Properties of Metals :

Metals are lustrous, malleable, ductile, good conductors of heat and electricity. Other properties include: State: Metals are solids at room temperature with the exception of mercury, which is liquid at room temperature (Gallium is liquid on hot days).

Hope this helps! :D

3 0
4 years ago
Gold has an atomic weight of 196.97 g/mol, and a density of 19.3 g/cm3. Approximately how many atoms are in a spherical gold nan
ale4655 [162]

<u>Answer:</u> The number of atoms in spherical gold nano particle are 26.918\times 10^4

<u>Explanation:</u>

  • To calculate the volume of sphere, we use the equation:

V=\frac{4}{3}\pi r^3

where,

r = radius of the sphere = 10nm=10^{-6}cm    (Conversion factor:  1nm=10^{-7}cm )

Putting values in above equation, we get:

V=\frac{4}{3}\times 3.14\times (10^{-6})^3\\\\V=4.19\times 10^{-18}cm^3

  • To calculate mass of of the substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Volume of gold = 4.19\times 10^{-18}cm^3

Density of gold = 19.3g/cm^3

Putting values in above equation, we get:

19.3g/cm^3=\frac{\text{Mass of gold}}{4.19\times 10^{-18}}\\\\\text{Mass of gold}=8.0867\times 10^{-17}g

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Mass of gold = 8.8067\times 10^{-17}g

Molar mass of gold = 196.97 g/mol

Putting values in above equation, we get:

\text{Moles of gold}=\frac{8.8067\times 10^{-17}g}{196.97g/mol}=4.47\times 10^{-9}moles

  • According to mole concept:

1 mole of an element contains 6.022\time 10^{23}  number of atom

So, 4.47\times 10^{-19} moles of gold will contain = 4.47\times 10^{-19}\times 6.022\times 10^{23}=26.918\times 10^4 number of atoms.

Hence, the number of atoms in spherical gold nano particle are 26.918\times 10^4

8 0
3 years ago
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