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2 years ago

6

The ratio of the number of hamsters to the number of mice in a pet store is 3 to 2. How many hamsters are there, if there are 12

mice?

1 answer:

aleksandrvk [35]2 years ago

6 0

Answer:

18

Step-by-step explanation:

you can do 12/2 to get 6 (the scale factor) and then multiply 3 by 6 and get 18

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What are the roots of the polynomial equation x^3 -6x=3x^2-8? Use a graphing calculator and a system of equations.

KIM [24]

Answer:

-4,1,3

Step-by-step explanation:

Because they all fit

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2 years ago

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Calculate the total budget and then fill in the missing percentages. You will use some of the answers given more than once. Tota

lutik1710 [3]

Total budget = $13,500

Donations = 12%

Taxes = 12%

Food = 26%

Clothing = 20%

Housing = 10%

and the rest are 5 %

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2 years ago

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Gabriel is making a mixture of compost and soil to use for a special plan he wants his final mix to be two part compost to 10 pa

kkurt [141]

Ten is mistakenly written by Tim in question.
Gabriel is making a mixture of compost and soil. In which he wants to mix 2 part compost to 10 parts potting soil. And he wants to end up with ten kilogram
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so, (2 / 12) x 10 kilogram of compost is used
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3 years ago

2x - 5y + 3z 5x + 9y - 2z

SIZIF [17.4K]

Answer:

3xz5+2x+4y−2z

Step-by-step explanation:

2x−5y+3z5x+9y−2z

=2x+−5y+3xz5+9y+−2z

Combine Like Terms:

=2x+−5y+3xz5+9y+−2z

=(3xz5)+(2x)+(−5y+9y)+(−2z)

=3xz5+2x+4y+−2z

7 0

2 years ago

The functions f (theta) and g (theta) are sine functions, where f (0) equals g (0) equals 0.The amplitude of f (theta) is twice

777dan777 [17]

If period of $f(\theta)$ is one-half the period of $g(\theta)$ and
<span> $g(\theta)$ has a period of 2π, then $T_{g} =2T_{f}=2 \pi$ and $T_{f}= \pi$ .
</span>
To find the period of sine function $f(\theta)=asin(b\theta+c)$ we use the rule $T_{f}= \frac{2\pi}{b}$ .
<span /><span />
f is sine function where f (0)=0, then c=0; with period $\pi$ , then $f(\theta)=asin 2\theta$ , because $T_{f}= \frac{2 \pi }{2} = \pi$ .

To find a we consider the condition $f( \frac{ \pi }{4} )=4$ , from where $asin2* \frac{\pi}{4} =a*sin \frac{ \pi }{2} =a=4$ .

If the amplitude of $f(\theta)$ is twice the amplitude of $g(\theta)$ , then $g(\theta)$ has a product factor twice smaller than $f(\theta)$ and while period of $g(\theta)$ <span> </span> is 2π and g(0)=0, we can write $g(\theta)=2sin\theta$ .

8 0

2 years ago