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maxonik [38]
3 years ago
9

Sarah found the mean of a set of numbers to be 205.09.how should she read this value out loud?

Mathematics
2 answers:
Elena-2011 [213]3 years ago
6 0
Two hundred and 5, point zero nine or 0 9
allochka39001 [22]3 years ago
3 0
Two hundred five and nine
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Linear equations<br>a+2b=-1 <br>2a+3b=23​
Keith_Richards [23]

Answer:

<h3>.2a + 4b = -2</h3><h3> 2a + 3b = 23</h3><h3><u>We</u><u> </u><u>subtr</u><u>act</u><u>.</u><u>.</u></h3><h3><u> </u><u> </u><u>0</u><u> </u><u>+</u><u> </u><u>b</u><u> </u><u>=</u><u> </u><u>-</u><u>2</u><u>5</u></h3>

<h3>a + (2×-25) = -1</h3><h3>a - 50 = -1</h3><h3>a = -1+50</h3><h3><u>a</u><u> </u><u>=</u><u> </u><u>4</u><u>9</u><u>.</u></h3>

<h3><u>a</u><u> </u><u>=</u><u> </u><u>4</u><u>9</u></h3><h3><u>b</u><u> </u><u>=</u><u> </u><u>-</u><u>2</u><u>5</u><u>.</u></h3>

Step-by-step explanation:

<h3><u>provin</u><u>g</u><u> my</u><u> </u><u>an</u><u>swer</u><u>.</u></h3>

<h3>a + 2b = -1</h3><h3>49 + (2×-25) = -1</h3><h3>49 - 50 = -1</h3>

<h3>2a + 3b = 23</h3><h3>(2×49) + (3×-25) = 23</h3><h3>98 + (-75) = 23</h3><h3>98 - 75 = 23</h3>
5 0
3 years ago
he books in a private library are classified as fiction and nonfiction. There are 400 books in the library. There are 40 more fi
vfiekz [6]
First, you have to set a system of equations to determine the number of fiction and of nonfiction books.Call f the number of fiction books and n the number of nonfiction books. Then 400 = f + n. And f = n + 40 => n = f - 40 => 400 = f + f - 40 => 400 - 40 = 2f => f = 360 / 2 = 180. Now to find the probability of picking two fiction books, take into account the the Audrey will pick from 180 fiction books out of 400, and Ryan will pick from 179 fiction books out of 399, so the probability will be<span> (180/ 400) * (179/399) = 0.20 (rounded to two decimals). Answer: 0.20</span>
3 0
3 years ago
Find the number z such that the proportion of observations that are less than z in a standard Normal distribution is 0.5414. (b)
Akimi4 [234]

Answer:

Part (a) The value of Z is 0.10396. Part (b) The value of Z is 0.410008.

Step-by-step explanation:

Consider the provided information.

Part (a)

In order to find the number z such that the proportion of observations that are less than z in a standard Normal distribution is 0.5414, simply find 0.5414 in the table and search for the appropriate Z-value.

Now, observing the table it can be concluded that the value of Z is 0.10396.

Part (b)

Consider the number 65.91%

The above number can be written as 0.6591.

Now, find 0.6591 in the table and search for the appropriate Z-value.

By, observing the table it can be concluded that the value of Z is 0.410008.

7 0
4 years ago
5 bags of dog food and 2 bags of cat food weigh 45 pounds. 6 pounds of dog weighs 45 pounds. All 6 of dog food weighs 45 pounds.
ZanzabumX [31]

Answer:

k = y/x

k = 30/2

k = 15 <=== constant of proportionality

Step-by-step explanation:

8 0
3 years ago
The tread life of tires mounted on light-duty trucks follows the normal probability distribution with a mean of 60,000 miles and
egoroff_w [7]

Answer:

86.64% probability that the mean tire life of these four tires is between 57,000 and 63,000 miles

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 60000, \sigma = 4000, n = 4, s = \frac{4000}{\sqrt{4}} = 2000

Suppose you bought a set of four tires, what is the likelihood the mean tire life of these four tires is between 57,000 and 63,000 miles

This is the pvalue of Z when X = 63000 subtracted by the pvalue of Z when X = 57000. So

X = 63000

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{63000 - 60000}{2000}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

X = 57000

Z = \frac{X - \mu}{s}

Z = \frac{57000 - 60000}{2000}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.9332 - 0.0668 = 0.8664

86.64% probability that the mean tire life of these four tires is between 57,000 and 63,000 miles

4 0
3 years ago
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