Answer:
She should select an industrial society (industrial population)
Step-by-step explanation:
An industrial society is a society that owes its operations to the use of technology which supports human usage of resources that allows high production turnouts.
An industrial society has high liking le preference for large population with a high capacity for external energy sources (e.g.fossil fuels) which in directly or indirectly increases the rate which resources are being used and also scale of production.
The resources could be human (labour) natural resources such as water, air, coal, natural gas, coal, etc. and it could also be technology advancements.
Answer:
Mercantilism allowed for government regulation of trade, which interfered with natural market forces.
The difference between Pre-Image and Image is given as follows:
- Image is the shape AFTER a transformation is the picture of the transformation.
- A transformation's preimage is the shape BEFORE the change.
<h3>How do you define relationships between Image and Preimage?</h3>
Usually, the difference between image and pre-image is the way or method of transformation.
<h3>What is transformation in math?</h3>
A transformation is a broad phrase covering four distinct methods of changing the shape and/or location of a point, line, or geometric figure.
The Pre-Image is the original shape of the item, and the Image during the transformation is the final shape and location of the object.
The types of transformation in math are;
- translation
- rotation
- reflection, and
- dilation.
Learn more about pre-image:
brainly.com/question/8405245
#SPJ1
Answer:
Rate of interest r = 2.83 % (Approx.)
Step-by-step explanation:
Given:
Amount invested p = $2,600
Amount get A = $4,300
Number of year n = 18
Find:
Rate of interest r
Computation:
A = p(1+r)ⁿ
4,300 = 2,600(1+r)¹⁸
(1+r)¹⁸ = 1.653846
Rate of interest r = 2.83 % (Approx.)
An= mth term.
an=a₁+(n-1)*d
a₁₂=41
a₁₅=140
a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d
a₁+11d=41 (1)
a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d
a₁+14d=140 (2)
With the equiations (1) and (2) build a system of equations
a₁+11d=41
a₁+14d=140
we solve it.
-(a₁+11d=41)
a₁+14d=140
--------------------
3d=99 ⇒d=99/3=33
a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322
an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n
an=-355+33n
To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
