Am sorry what can you be more specific
Answer:
I think all will display the same value
Explanation:
Sorry if this is wrong
Answer:
1.603 s
Explanation:
Given that
Initial mass, = 0.45 kg
Initial period, = 1.45 s
Initial radius, = 0.14 m
Final mass, = 0.55 kg
Final period, = ?
Final radios, = 0.14 m
Since we are finding the rotation period of two masses of same radius, we can assume that the outward force is the same in both cases. This means that
m₁r₁ω₁² = m₂r₂ω2²
Where, ω = 2π/T, on substituting, we have
0.45 * 0.14 * (2π / 1.45)² = 0.550 * 0.14 * (2π / T₂)²
0.45 / 1.45² = 0.550 / T₂²
T₂² = 0.550 * 1.45² / 0.45
T₂² = 2.56972
T₂ = √2.56972
T₂ = 1.603 sec
Answer: 0.17hp
Explanation:
Power output = power input × 85%
Power output = power input × 0.85
Power input = IV/0.85
Power input = 9×12/0.85
Power input = 108/0.85
= 127.058 watts
Converting to horse power = 127.058W × 1horse power/745.7W
= 127.058 × 0.001341
= 0.17hp
Answer:
T=189.15 N
Explanation:
As we know that for downward motion
F acting = F (weight) - Tension T
m a = mg - T
⇒ T = m (g - a)
T = 29.1 kg ( 9.8 m/s² - 3.3 m/s²)
T=189.15 N
