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notsponge [240]
3 years ago
9

About how often does a 1-kilometer object strike the earth? about how often does a 1-kilometer object strike the earth? every ye

ar every million years every billion years
Physics
1 answer:
sleet_krkn [62]3 years ago
3 0
I’m done with my homework done and I got to go to get my homework done and I got to go to get my homework done
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A toaster is plugged into a 132 volt household circuit it draws the amps of current If you use a toaster 2 hours a week how much
Ne4ueva [31]
There is a missing data in the text of the problem: the current drawn is 0.5 A (found on internet)

Solution:
The power used by the toaster is the product between the voltage V and the current I:
P=VI=(132 V)(0.5 A)=66 W=0.066 kW

The toaster is used for a time of 2 hours: t=2h, therefore the energy used is equal to
E=Pt =(0.066 kW)(2 h)=0.132 kWh
8 0
3 years ago
A bare 4 AWG copper conductor Installed horizontally near the bottom or vertically, and within that portion of a concrete foun d
neonofarm [45]

Answer:

20 ft

Explanation:

This is the length where the direct contact could be used as ground electrode

4 0
3 years ago
A 1,000 kg ball traveling at 5 m/s would have
jonny [76]

Answer:

15 because 5×5×5 is the same thing as 5×3 which equals to 15

6 0
3 years ago
Read 2 more answers
A block of mass 200g is oscillating on the end of a horizontal spring of spring constant 100 N/m and natural length 12 cm. When
malfutka [58]

In order to determine the acceleration of the block, use the following formula:

F=ma

Moreover, remind that for an object attached to a spring the magnitude of the force acting over a mass is given by:

F=kx

Then, you have:

ma=kx

by solving for a, you obtain:

a=\frac{kx}{m}

In this case, you have:

k: spring constant = 100N/m

m: mass of the block = 200g = 0.2kg

x: distance related to the equilibrium position = 14cm - 12cm = 2cm = 0.02m

Replace the previous values of the parameters into the expression for a:

a=\frac{(\frac{100N}{m})(0.02m)}{0.2\operatorname{kg}}=10\frac{m}{s^2}

Hence, the acceleration of the block is 10 m/s^2

8 0
1 year ago
If the jet is moving at a speed of 1300 km/h at the lowest point of the loop, determine the minimum radius of the circle so that
Natalka [10]

Answer:

R = 2216m and The normal force of the seat on the pilot is 5008N

Explanation:

See attachment below please.

5 0
3 years ago
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