Answer:
The right response will be "450 volts".
Explanation:
The given values are:
R1 = 4.00 cm
R2 = 6.00 cm
q1 = +6.00 nC
q2 = −9.00 nC
As we know,
The potential difference between the two shell's difference will be:
⇒ ![\Delta V=K[(\frac{q1}{R1}+\frac{q2}{R2})-(\frac{q1}{R1} +(\frac{q2}{R2}))]](https://tex.z-dn.net/?f=%5CDelta%20V%3DK%5B%28%5Cfrac%7Bq1%7D%7BR1%7D%2B%5Cfrac%7Bq2%7D%7BR2%7D%29-%28%5Cfrac%7Bq1%7D%7BR1%7D%20%2B%28%5Cfrac%7Bq2%7D%7BR2%7D%29%29%5D)
![=K[\frac{q1}{R2}-\frac{q1}{R1} ]](https://tex.z-dn.net/?f=%3DK%5B%5Cfrac%7Bq1%7D%7BR2%7D-%5Cfrac%7Bq1%7D%7BR1%7D%20%5D)
On substituting the values, we get
![=(9\times 10^9)[\frac{6\times 10^{-9}}{0.04}-\frac{6\times 10^{-9}}{0.06}]](https://tex.z-dn.net/?f=%3D%289%5Ctimes%2010%5E9%29%5B%5Cfrac%7B6%5Ctimes%2010%5E%7B-9%7D%7D%7B0.04%7D-%5Cfrac%7B6%5Ctimes%2010%5E%7B-9%7D%7D%7B0.06%7D%5D)
Δ 
I may be wrong, but I think you're trying to say that Planet-A is
<em>3 times as far from the sun</em> as Planet-C is.
If that's the real question, then the answer is that the period of Orbit-A
is about<em> 5.2</em> times as long as the period of Orbit-C .
Orbital period ≈ (proportional to) (the orbital distance) ^ 3/2 power.
This was empirically demonstrated about 350 years ago by Johannes
and his brilliant Kepple, and derived about 100 years later by Newton
from his formula for the forces of gravity.
Answer:
2.210N
Explanation:
Workdone = Force x distance
Distance = 38m , Workdone = 84J
Hence 84J = Force x 38m
Force = 84J / 38m
Force = 2.210N =2.2N
Answer:
+ 5 m/s
Explanation:
change in displacement = ΔX=final position - initial position
ΔX = 0-(-5) =0+5 =+ 5 m
average velocity = ΔX/t
= +5/1
= + 5 m/s
positive sign shows that ball rolls towards right
<u>Answer:</u>
<em>Resultant of two vectors having opposite direction is the difference of the two displacements having the same direction as the larger vector.
</em>
<u>Explanation:</u><u>
</u>
Resultant of two vectors is obtained by performing the vector addition operation. When the directions of both vectors are same the resultant’s direction will also be the same as the inputs. When two vectors have opposite directions, one direction will be taken positive making one vector positive and the other negative.
By performing addition of a positive and negative number we are actually taking the difference between both. Thus performing vector addition of two vectors with opposite directions is equivalent to finding the difference between the vectors. Consider a system consisting of a solid block, on which two forces F1 and F2 act in the opposite direction.
One force will be considered positive and the other is considered negative. The resultant is given by the difference of two force vectors. Displacement of the block will be in the direction of the greater force.
