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tresset_1 [31]
3 years ago
14

Let v(t)=t2−2tv(t)=t2−2t be the velocity, in feet per second, of an object at time tt, in seconds.

Mathematics
2 answers:
kirza4 [7]3 years ago
6 0
Thee function is given as:

<span>v(t)=t^2−2tv(t)=t^2−2t 

</span>(a) What is the initial velocity? 

Base from the function, the initial velocity would be zero.

(b) When does the object have a velocity of zero?

It would be during time zero. Also, at a time equal to two.
Anni [7]3 years ago
3 0

Answer:

v(0) =0

t=0,2

Step-by-step explanation:

Given that velocity in feet per second of an object  at time t in seconds is given by the quadratic equation

v(t) = t^2-2t

Initial velocity is the velocity at time 0.

Substitute t=0 in v(t)

a) Initial velocity = v(0) = 0^2-2(0)=0

b) Equate velocity function to 0 and solve for t.

v(t) = t^2-2t=0\\t(t-2)=0\\t=0,2

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