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fenix001 [56]
3 years ago
9

Maya has a dog and it wants to be pet

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

so what is the question?

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What is the slope of a line perpendicular to the line passing through (1, -3) and (-4, 7)?
andrezito [222]

Answer:

-2

Step-by-step explanation:

m=\frac{y2-y1}{x2-x1}

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Please help asap !!!​
Illusion [34]

Answer: 2.)non function 3.)non function 4.) function 5.)non function 6.) non function 7.)function 8.)non function PART B 1.)non function 2.)function 3.) function

Step-by-step explanation: a function is when the domain (x) all each have one answer like (-2.6)(7,4)(8,6) there can be repeating ranges (y) just not domains.

A non function is when one domain (x) has multiple ranges(y) like (7,2)(-9,6)(7,9) the 7 repeats twice giving it two ranges, which causes it to be non functional. hope that helped :))

6 0
3 years ago
PLEASE HELP! I'm on a timer!
arlik [135]
The equation of a circle uses the following formula:

(x - h)^{2} + (y - k)^{2} = r^{2}

The center of the circle is given by (h,k). Therefore, h = -2, and k = -5. r = 1, so we can find the equation from the information given to us.

Plug in your values.

(x + 2)^{2} + (y + 5)^{2} = 1^{2}

1^{2} = 1

The equation of this circle is as follows:

(x + 2)^{2} + (y + 5)^{2} = 1
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3 years ago
You invest AED 5000 in a saving account that earns 4% interest each year. If you do not use the account for a year, how much mon
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2 years ago
Determine g(x + a) – g(x) for the following function.<br> g(x) = 5x2 + 2x
dusya [7]

Answer:

g(x + a) - g(x) = 10ax + 5a^2 + 2a

Step-by-step explanation:

We are given the function:

g(x) = 5x^2 + 2x

And we want to determine:

\displaystyle g(x+a) - g(x)

Substitute:

\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right]    \end{aligned}

And simplify:

\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \\  \\ &= \left(5(x^2 + 2ax + a^2) + (2x + 2a) \right) + \left(-5x^2 - 2x\right) \\ \\ &= \left((5x^2 + 10ax + 5a^2) + (2x + 2a)\right) + \left(-5x^2 - 2x\right) \\ \\ &= (5x^2-5x^2) + (10ax + 2x - 2x) + (5a^2+2a)     \\ \\ &= 10ax + 5a^2 + 2a \end{aligned}

In conclusion:

g(x + a) - g(x) = 10ax + 5a^2 + 2a

3 0
3 years ago
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