Answer:
-2
Step-by-step explanation:
m=
Answer: 2.)non function 3.)non function 4.) function 5.)non function 6.) non function 7.)function 8.)non function PART B 1.)non function 2.)function 3.) function
Step-by-step explanation: a function is when the domain (x) all each have one answer like (-2.6)(7,4)(8,6) there can be repeating ranges (y) just not domains.
A non function is when one domain (x) has multiple ranges(y) like (7,2)(-9,6)(7,9) the 7 repeats twice giving it two ranges, which causes it to be non functional. hope that helped :))
The equation of a circle uses the following formula:

The center of the circle is given by (h,k). Therefore, h = -2, and k = -5. r = 1, so we can find the equation from the information given to us.
Plug in your values.


The equation of this circle is as follows:
bhot me 156792652 uhh tired Dustin often of red ohh if em it's em it's em it's em it's em it's em
Answer:

Step-by-step explanation:
We are given the function:

And we want to determine:

Substitute:
![\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7Dg%28x%20%2B%20a%29%20-%20g%28x%29%20%26%3D%5Cleft%5B5%28x%2Ba%29%5E2%20%2B%202%28x%2Ba%29%5Cright%5D%20-%5Cleft%5B5x%5E2%2B2x%5Cright%5D%20%20%20%20%5Cend%7Baligned%7D)
And simplify:
![\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \\ \\ &= \left(5(x^2 + 2ax + a^2) + (2x + 2a) \right) + \left(-5x^2 - 2x\right) \\ \\ &= \left((5x^2 + 10ax + 5a^2) + (2x + 2a)\right) + \left(-5x^2 - 2x\right) \\ \\ &= (5x^2-5x^2) + (10ax + 2x - 2x) + (5a^2+2a) \\ \\ &= 10ax + 5a^2 + 2a \end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7Dg%28x%20%2B%20a%29%20-%20g%28x%29%20%26%3D%5Cleft%5B5%28x%2Ba%29%5E2%20%2B%202%28x%2Ba%29%5Cright%5D%20-%5Cleft%5B5x%5E2%2B2x%5Cright%5D%20%5C%5C%20%20%5C%5C%20%26%3D%20%5Cleft%285%28x%5E2%20%2B%202ax%20%2B%20a%5E2%29%20%2B%20%282x%20%2B%202a%29%20%5Cright%29%20%2B%20%5Cleft%28-5x%5E2%20-%202x%5Cright%29%20%5C%5C%20%5C%5C%20%26%3D%20%5Cleft%28%285x%5E2%20%2B%2010ax%20%2B%205a%5E2%29%20%2B%20%282x%20%2B%202a%29%5Cright%29%20%2B%20%5Cleft%28-5x%5E2%20-%202x%5Cright%29%20%5C%5C%20%5C%5C%20%26%3D%20%285x%5E2-5x%5E2%29%20%2B%20%2810ax%20%2B%202x%20-%202x%29%20%2B%20%285a%5E2%2B2a%29%20%20%20%20%20%5C%5C%20%5C%5C%20%26%3D%2010ax%20%2B%205a%5E2%20%2B%202a%20%5Cend%7Baligned%7D)
In conclusion:
