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2 years ago

-11 - 5a = 6(5a + 4) but I really need it in mathematical form.

Mathematics

1 answer:

ella [17]2 years ago

6 0

Answer:

Step-by-step explanation:

In this equation what is strange is probably using the letter a as the unknown, but this is a matter of choice we could have calle y or z for that matter. Then we will treat it ans any other equation and solve it.

-11 -5a = 6(5a+4)

-11 -5a= 30a + 24

-11 - 24 = 30a + 5a (placing the unknown a in the rght side and the numbers in the left to solve the equation)

- 35 = 35a

-35/35 = a

- 1= a

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The planet to have the biggest mass is Jupiter

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PLEASE HELP (100 POINTS)

Artyom0805 [142]

$\\ \rm\Rrightarrow f(x)=-5cos\dfrac{x}{2}+5$

Compare to standard equation of SHM

$\\ \rm\Rrightarrow y=Acos(\omega x+\phi)$

Here

Amplitude=A=-5

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If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?

Keith_Richards [23]

$\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}$

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

$\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
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\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}$

so, the domain is all real numbers EXCEPT that one.

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Helen [10]

Answer:

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Step-by-step explanation:

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-11 - 5a = 6(5a + 4) but I really need it in mathematical form. ​

-11 - 5a = 6(5a + 4) but I really need it in mathematical form.