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3 years ago

-11 - 5a = 6(5a + 4) but I really need it in mathematical form.

Mathematics

1 answer:

ella [17]3 years ago

6 0

Answer:

Step-by-step explanation:

In this equation what is strange is probably using the letter a as the unknown, but this is a matter of choice we could have calle y or z for that matter. Then we will treat it ans any other equation and solve it.

-11 -5a = 6(5a+4)

-11 -5a= 30a + 24

-11 - 24 = 30a + 5a (placing the unknown a in the rght side and the numbers in the left to solve the equation)

- 35 = 35a

-35/35 = a

- 1= a

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Calculate the product 78.93 times 32.45

Alona [7]

Answer:

2561.2785

Step-by-step explanation:

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2 years ago

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Determine the equation of each line with the following properties:

iris [78.8K]

Answer:

a) y =2/3 x + 7.

b) x = -1

c) y = -4/5 x - 1/5

d) y = -3/2 x + 5/2.

Step-by-step explanation:

a) Intercept form y = mx + b where m = 2/3 and b = 7

b) y can take any value but x is always -1.

c) Slope m = (-1-3)/ (1 - -4)

= -4/5

Using point-slope form where m = -4/5 and x1 y1 = 1 , -1:

y - y1 = m(x - x1)

y - -1 = -4/5(x - 1)

y + 1 = -4/5x + 4/5

y = -4/5 x - 1/5

d) The slope m of the line perpendicular to this line is:

-1 / 2/3

m = -3/2.

When x = -1 , y = 4 so using the slope intercept form of a line

y = mx + b

4 = -3/2 * -1 + b where b = the y-intercept.

4 = 3/2 + b

b = 4 - 3/2 = 5/2.

The equation is y = -3/2 x + 5/2.

3 0

3 years ago

5. On the cardiac ward of a local hospital, there are 7 nursing assistants. The seven assistants have 7, 8, 5, 9, 10, 10, and 14

almond37 [142]

Answer:

Option OD - 9

Step-by-step explanation:

Given : On the cardiac ward of a local hospital, there are 7 nursing assistants. The seven assistants have 7, 8, 5, 9, 10, 10, and 14 patients, respectively, that they assist.

To find : What is the average number of patients per nursing assistant?

Solution :

The average number of patients per nursing assistant is given by the division of sum of number of patients by total number of nursing.

So, $\text{Average} =\frac{\text{Sum of patients}}{\text{Number of assistants}}$