All categories

3 years ago

What is the gradient of the blue line Attachment below!!!!!!!!!!!

Mathematics

1 answer:

mr_godi [17]3 years ago

6 0

Answer:

-3 Or 3 it could be any one of them

Step-by-step explanation:

-3 or 3

Rise/run so an

You might be interested in

Find the probability of atleast three successes in six trials of a binomial experiment in which the probability of success is 50

yan [13]

The binomial cumulative probability with p=0.5 for 3+ successes is as follows:

$P(3+)=\sum_{k=3}^6 {{6}\choose{k}}p^k(1-p)^{6-k}$

for p=0.5 (50% success rate) it becomes:

$P(3+)=\sum_{k=3}^6 {{6}\choose{k}}0.5^6=\frac{21}{32}=0.65625$

the probability is 0.65625, or about 66%

7 0

3 years ago

Plz help me!!with this!!

ikadub [295]

the surface area of that rectangular prism is 247.5.

7 0

3 years ago

A theater has 28 rows of 38 seats downstairs and 14 rows of 26 seats upstairs.How many seats does the theater have?

Triss [41]

For downstairs- 28 x 38= 1064

For upstairs- 26 x 14= 364

All together- 1064 + 364= 1428

So.... 1428 seats in total.

Hope this helped! :)

3 0

2 years ago

-2 1/3 - (-5) = ? can someone please help me ty!

Eddi Din [679]

Answer: 8/3

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).

storchak [24]

Answer:

$P=16.53\ units$

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(0)^{2}}$

$d=\sqrt{1}$

$dPQ=1\ unit$

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

$d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-5)^{2}+(-4)^{2}}$

$dQR=\sqrt{41}\ units$

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

$d=\sqrt{(3+2)^{2}+(-2+2)^{2}}$

$d=\sqrt{(5)^{2}+(0)^{2}}$

$dRS=5\ units$

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(-4)^{2}}$

$dPS=\sqrt{17}\ units$

step 5

Find the perimeter

$P=PQ+QR+RS+PS$

substitute the values

$P=1+\sqrt{41}+5+\sqrt{17}$

$P=6+\sqrt{41}+\sqrt{17}$

$P=16.53\ units$

5 0

3 years ago