Answer:
3(2-2) * 3(20-2)
3(0) * 3(18)
0 * 54 = 0
Step-by-step explanation:
3(2-2) * 3(20-2)
3(0) * 3(18)
0 * 54 = 0
Prime factorization of 5·2·5=5^2·2
95% of red lights last between 2.5 and 3.5 minutes.
<u>Step-by-step explanation:</u>
In this case,
- The mean M is 3 and
- The standard deviation SD is given as 0.25
Assume the bell shaped graph of normal distribution,
The center of the graph is mean which is 3 minutes.
We move one space to the right side of mean ⇒ M + SD
⇒ 3+0.25 = 3.25 minutes.
Again we move one more space to the right of mean ⇒ M + 2SD
⇒ 3 + (0.25×2) = 3.5 minutes.
Similarly,
Move one space to the left side of mean ⇒ M - SD
⇒ 3-0.25 = 2.75 minutes.
Again we move one more space to the left of mean ⇒ M - 2SD
⇒ 3 - (0.25×2) =2.5 minutes.
The questions asks to approximately what percent of red lights last between 2.5 and 3.5 minutes.
Notice 2.5 and 3.5 fall within 2 standard deviations, and that 95% of the data is within 2 standard deviations. (Refer to bell-shaped graph)
Therefore, the percent of red lights that last between 2.5 and 3.5 minutes is 95%
I disagree. The first one is false. No exponent rules apply if the bases AND the exponents are different.
The second one is true. Bases are the sane so you add exponents. You get 3 to the -5 power. Written with positive exponents it’s 1/3 to the 5.
