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3 years ago

What is the probability of picking an "m" in the word "Mississippi"

2 answers:

3 0

There are 11 letters in Mississippi. One letter is an M. You have a 1/11 chance of drawing an M if you randomly pick a letter.

Yuri [45]3 years ago

3 0

Mississippi = 11 letters

there is 1 M

so you have a 1/11 probability of picking M

You might be interested in

Original price is 150 new price 189 what is the percent

viktelen [127]

Answer:

The percent is 26%

Step-by-step explanation:

189 divided by 150 is 1.26 but since the original price is $150 the percent is 100% and 189 is 126% so the percent difference is 26%.

4 0

3 years ago

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $21.506$ to $24.493$

Hence Confidence interval : $21.506$ to $24.493$

3 0

3 years ago

Read 2 more answers

What is the product of 1 and 1 3rd and 7/10

Dmitrij [34]

The correct answer is 14/15. To answer this problem, it would help to change the mixed number into an improper fraction.

1 1/3
4/3 Multiply 3 by 1, and then add 1 and put 4 over 3.

4/3 x 7/10 Now, multiply both numbers by each other. Since we're multiplying, we don't need to find a least common denominator.
28/30 4 x 7 = 28; 3 x 10 = 30
14/15 Since 28 and 30 are divisible by 2, we need to simplify the answer.

The correct answer is 14/15.

Hope this helps!

3 0

3 years ago

BRAINLIEST PLEASE HELP!!<br> 6. Find x and the measures of the indicated parts.<br> AS

AleksandrR [38]

Answer:

Step-by-step explanation:

Δ CBA and Δ SAR are similar

Thus the ratios of corresponding sides are equal, that is

$\frac{CB}{SA}$ = $\frac{CA}{SR}$ , substituting values gives

$\frac{5}{x}$ = $\frac{10}{4}$ ( cross- multiply )

10x = 20 ( divide both sides by 10 )

x = 2

Thus

AS = x = 2

6 0

3 years ago

I need help. I don't understand this problem.

Ksju [112]

Yes they are congruent.
Exactly equal in size and shape. Congruent sides or segments have the exact same length. Congruent angles have the exact same measure. For any set of congruent geometric figures, corresponding sides, angles, faces, etc. are congruent.

8 0

3 years ago

Read 2 more answers