X+3=61
x=61-3=58
58+37=95
180-95=85
so x=58 and y=85
Answer:
6
Step-by-step explanation:
84 = 3 x 28
56 = 2 x 28
Minimum number of square plot, each square is 28 x 28
the number is 3 x 2 = 6
Answer:190.40 dollars.
Step-by-step explanation:
Okay if we know that Jess bought 3 pairs for 71 dollars divide 71 by 3 then multiply that by 8.
4sin²(x) = 5 - 4cos(x)
4{¹/₂[1 - cos(2x)]} = 5 - 4cos(x)
4{¹/₂[1] - ¹/₂[cos(2x)]} = 5 - 4cos(x)
4[¹/₂ - ¹/₂cos(2x)] = 5 - 4cos(x)
4[¹/₂] - 4[¹/₂cos(2x)] = 5 - 4cos(x)
2 - 2cos(2x) = 5 - 4cos(x)
- 2 - 2
-2cos(2x) = 3 - 4cos(x)
-2[2cos²(x) - 1] = 3 - 4cos(x)
-4cos²(x) + 2 = 3 - 4cos(x)
- 2 - 2
-4cos²(x) = 1 - 4cos(x)
-4cos²(x) + 4cos(x) - 1 = 0
4cos²(x) - 4cos(x) + 1 = 0
[2cos(x) - 1]² = 0
2cos(x) - 1 = 0
+ 1 + 1
2cos(x) = 1
2 2
cos(x) = ¹/₂
cos⁻¹[cos(x)] = cos⁻¹(¹/₂)
x = 60, 300
x = π/3, 5π/3
[0, 2π) = 0 ≤ x < 2π
[0, 2π) = 0 ≤ π/3 ≤ 2π or 0 ≤ 5pi/3 < 2π
Answer:
0.001145
Step-by-step explanation:
Given that you are certain to get 3 jacks when selecting 51 cards from a shuffled deck.
When we draw 3 cards from 51 cards, we keep one card aside
The card can be either Jack or non Jack
Prob (the left over card to be Jack) = P(A) = 
Prob (the left over card to be non jack ) = P(B) = 
A and B are mutually exclusive and exhaustive
Let drawing 3 Jacks be the event C
P(C) = P(AC)+P(BC)
P(BC) = P(B)*P(C/B)\\
= \frac{28}{52} (4/51C3)\\
=1.034(10^{-4}
Adding we get
P(C)
= 
