The factoring method which can be considered for such a cubic tetranomial expression is; factor by grouping sum of cubes.
<h3>What factoring method can be considered for the polynomial?</h3>
It follows from the task content that the order of the Polynomial is 3 and the polynomial is a tetranomial as it contains 4 terms.
On this note, since 3x³ is not a perfect cube, it follows that the best factorisation method for such a polynomial is; factor by grouping sum of cubes.
Read more on factorisation;
brainly.com/question/25829061
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Pythagoras Theroem.
Leg₁²+leg₂²=hypotenuse²
Data:
Leg₁=48
hypotneuse=80
(48)²+ leg₂²=(80)²
2304+leg₂²=6400
leg₂²=6400-2304
leg₂²=4096
leg₂=√4096
leg₂=64
Answer: B. 64
-X + 5Y = 1
X = 5Y - 1
4X + 3Y = -4
Substitute
4(5Y - 1) + 3Y = -4
Simplify
20Y - 4 + 3Y = -4
23Y = 0
Y = 0
X =-1
~Hai <3
