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2 years ago

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The first day of Alex's trip was a Monday. What day of the week was Day 393939 of Alex's trip? Select the correct answer. Day 39

3939 of Alex's trip was a

1 answer:

Evgen [1.6K]2 years ago

8 0

Answer:

Thursday.

Step-by-step explanation:

We have that the first day of Alex's trip was a Monday, that is to say that the next Monday will be obtained by adding 7 to the previous numbers.

1 + 7 = 8

8 + 7 = 15

15 + 7 = 22

22 + 7 = 29

29 + 7 = 36

We have that the 36th is a Monday, therefore:

37, Tuesday

38, Wednesday

39, Thursday

In other words, the 39th would be Thursday.

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Answer:

C. -4

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2 years ago

Solve for x: 2x - 2 > 4x + 6

laiz [17]

Isolate the x. Subtract 4x from both sides, and add 2 to both sides

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2x - 4x > 6 + 2

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Isolate the x. Divide -2 from both sides. Note that you are <em>dividing a negative number</em>. When doing so, flip the sign.

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3 years ago

1)12-5x-4kx=y, solve for x

sveticcg [70]

12-x(5-4k)=y
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2 years ago

Read 2 more answers

There are approximately 7.7 billion humans on Earth. If the virus spreads beyond the 200-person town, how long will it be until

eimsori [14]

Answer:

25.2 weeks until everyone on the planet is infected

Step-by-step explanation:

The number of infected people after t weeks has the following format:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the initial number of infected people and r is the growth rate, as a decimal.

The number of infected people doubles every week

This means that $P(1) = 2P(0)$

So

$P(t) = P(0)(1+r)^{t}$

$2P(0) = P(0)(1+r)$

$1 + r = 2$

$r = 1$

So

$P(t) = P(0)*(2)^{t}$

200-person town

This means that $P(0) = 200$

So

$P(t) = P(0)*(2)^{t}$

$P(t) = 200*(2)^{t}$

How long will it be until everyone on the planet is infected?

This is t for which P(t) = 7700000000[/tex]

So

$P(t) = 200*(2)^{t}$

$7700000000 = 200*(2)^{t}$

$2^{t} = \frac{7700000000}{200}$

$\log{2^{t}} = \log{\frac{7700000000}{200}}$

$t\log{2} = \log{\frac{7700000000}{200}}$

$t = \frac{\log{\frac{7700000000}{200}}}{\log{2}}$

$t = 25.2$

25.2 weeks until everyone on the planet is infected

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2 years ago

On a coordinate plane, the segment with endpoints (10, 40) and (70, 120) is

OlgaM077 [116]

Answer:

The length of the resulting segment is 500.

Step-by-step explanation:

Vectorially speaking, the dilation is defined by following operation:

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$ (1)

Where:

$O(x,y)$ - Center of dilation.

$P(x,y)$ - Original point.

$k$ - Scale factor.

$P'(x,y)$ - Dilated point.

First, we proceed to determine the coordinates of the dilated segment:

( $P(x,y) = (10, 40)$ , $Q(x,y) = (70, 120)$ , $O(x,y) = (0,0)$ , $k = 5$ )

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$

$P(x,y) = (0,0) +5\cdot [(10,40)-(0,0)]$

$P'(x,y) = (50,200)$

$Q'(x,y) = O(x,y) + k\cdot [Q(x,y)-O(x,y)]$

$Q' (x,y) = (0,0) +5\cdot [(70,120)-(0,0)]$

$Q'(x,y) = (350, 600)$

Then, the length of the resulting segment is determined by following Pythagorean identity:

$l_{P'Q'} = \sqrt{(350-50)^{2}+(600-200)^{2}}$

$l_{P'Q'} = 500$

The length of the resulting segment is 500.

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2 years ago