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Veseljchak [2.6K]
3 years ago
6

Box A has a volume of 48 cubic meters. Box B is similar to box A. To create box B, box A's dimensions were doubled. What is the

volume of box B? a. 24 m3 b. 96 m3 c. 288 m3 d. 384 m3
Mathematics
1 answer:
ELEN [110]3 years ago
3 0
The answer is d. 384 m3.

The volume (V) of the box is:
V = l × w × h
l - the length of the box
w - the width of the box
h - the height of the box

If V1 = 48 m³ = l × w × h and all its dimensions are doubled to create box B, then:
V2 = 2l × 2w × 2h = 2 × 2 × 2 × l × w × h = 8 x l × w × h

We know that l × w × h is 48 m³, so:
V2 = 8 x l × w × h = 8 × 48 = 384 m³
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using the midpoint formula find the coordinates of the midpoint 9f each sigment with end points (4,2),(-5,-1)​
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Answer:

The midpoint of the segment is (-0.5,0.5).

Step-by-step explanation:

Midpoint of a segment:

The midpoint of a segment is given by the mean of its coordinates.

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y-coordinates: 2 and -1

x-coordinate of the midpoint:

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A blueprint for a garage has a scale of 1.5 cm to 3 cm. on the blueprint, the lenght of one wall is 8cm. If w represents the len
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Read 2 more answers
The rate at which rain accumulates in a bucket is modeled by the function r given by r(t)=10t−t^2, where r(t) is measured in mil
mars1129 [50]

Answer:

36 milliliters of rain.

Step-by-step explanation:

The rate at which rain accumluated in a bucket is given by the function:

r(t)=10t-t^2

Where r(t) is measured in milliliters per minute.

We want to find the total accumulation of rain from <em>t</em> = 0 to <em>t</em> = 3.

We can use the Net Change Theorem. So, we will integrate function <em>r</em> from <em>t</em> = 0 to <em>t</em> = 3:

\displaystyle \int_0^3r(t)\, dt

Substitute:

=\displaystyle \int_0^3 10t-t^2\, dt

Integrate:

\displaystyle =5t^2-\frac{1}{3}t^3\Big|_0^3

Evaluate:

\displaystyle =(5(3)^2-\frac{1}{3}(3)^3)-(5(0)^2-\frac{1}{3}(0)^3)=36\text{ milliliters}

36 milliliters of rain accumulated in the bucket from time <em>t</em> = 0 to <em>t</em> = 3.

4 0
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