Answer:
no. it isn't necessary.
Step-by-step explanation:
there are some cases where adding two repeating decimals results in a sum which does not have a repeating decimal. For example,
1 over 3
+
2 over 3
=
3 over 3
=1
. Thus, the sum of two repeating decimals is not always a repeating decimal.
Step-by-step explanation:
Given the equation that represents this order expressed as;
The number of tiles = 12b + 38 where;
b is the the number of bundles ordered
If a customer needs 150 tiles, the total number of bundles ordered can be gotten by simply substituting The number of tiles into the modeled equation and find the value of b. This is as shown below;
On substituting;
150 = 12b + 38
12b = 150 - 38
12b = 112
b = 112/12
b = 9.33
b ≈ 9 bundles
We need to round up the problem because the number of tiles can not be in fraction but as whole numbers.
Answer:
1: (4,1) x=4 y=1
2: (1,10) x=1 y=10
3: (-25/4,5) x= -25/4 y=5
Step-by-step explanation:
It would be a lot to explain all three so if you really need it just ask
(12ab)(3t) = (12 · 3)(abt) = 36abt
So first let’s combine like terms and add 4/9x and 1/5x together to get 29/45x =58. Next, multiply 58 by 45/29 to isolate x, so x=90
