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Nat2105 [25]
3 years ago
12

Three times a number decreased by 9

Mathematics
2 answers:
DedPeter [7]3 years ago
7 0

Answer:

I do not know what you want, but the equation is 3x - 9

Step-by-step explanation:

Nady [450]3 years ago
7 0

Answer:

3a - 9

Step-by-step explanation:

Three times a number decreased by 9:

3a - 9

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What is the area of this composite figure?
Mkey [24]

We have two congruent trapezoids.

The formula of an area of a trapezoid:

A=\dfrac{base_1+base_2}{2}\cdot\ height

We have:

base_1=210\ mm\\\\base_2=150\ mm\\\\height=55\ mm

Substitute:

A=\dfrac{210+150}{2}\cdot55=\dfrac{360}{2}\cdot55=180\cdot55=9,900\ mm^2

Answer:

2A=2\cdot9,900\ mm^2=19,800\ mm^2

6 0
3 years ago
The cost of a piece of carpet is dependent on its area, in square feet, as shown in the graph.
Bess [88]

Answer:

A. false

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C. $290

Step-by-step explanation:

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3 0
3 years ago
Solve the equation: (x − 4)(x − 3) = 0
trasher [3.6K]

Answer:

x=4, x=3

Step-by-step explanation:

This is most often the format taken from the polynomial form of this problem, which is x^2-7x+12, and when it is in this format you just take each set of numbers within each parenthesis and set it to zero, then solve. In this case, x can be equal to either 3 or 4.

8 0
3 years ago
Hi! ❤️ , im looking for some help here. ill give brainliest if able to.
olchik [2.2K]

Hello there! The solution of your question has been given below.

<h3>Solution:</h3>

{6}^{ - 2}  \\  = ( \frac{1}{6} ) ^{2}  \\  =  \frac{ {1}^{2} }{ {6}^{2} }  \\  =  \frac{1}{36}

<h3>Answer:</h3>

Option B.

\frac{1}{36}

5 0
3 years ago
Which table represents a linear function?​
Andrew [12]

Answer:

The first table is the only table representing a linear function.

Step-by-step explanation:

<em>" You can tell if a table is linear by looking at how X and Y change. If, as X increases by 1, Y increases by a constant rate, then a table is linear. You can find the constant rate by finding the first difference. This table is linear."</em>

<em />

<em />

<em />

<em />

<em>P.S.</em>

<em />

<em>( thanks to G00GLE for the anwers, hat's off to the internet :^) </em>

8 0
3 years ago
Read 2 more answers
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