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4 years ago

The ___ -centimeter side corresponds to the y-centimeter side

Mathematics

1 answer:

Ann [662]4 years ago

5 0

Answer:

x has to be the answer because on an coordinate plane x and y is mentioned

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Simplify.<br><br><br><br> Enter your answer, in simplest radical form, in the box.

puteri [66]

24.75 rounded might be 25

5 0

3 years ago

Read 2 more answers

1. Slove the system of equations, first by graphing, and then algebraically. (8 points) y=x-2 and y=-2x+7

Anton [14]

The solution of the equation is $x=3$ and $y=1$

Explanation:

The equations are $y=x-2$ and $y=-2 x+7$

First we shall solve the equation graphically.

The image of the graph is attached below.

This contains the solution to the system of equations.

The equations $y=x-2$ and $y=-2 x+7$ are plotted on the graph.

The intersection of these two equations are the solutions of the system of equations.

Thus, the intersection of the two equations are $x=3$ and $y=1$

Now, we shall solve the equation algebraically.

Let us solve the equation using substitution method.

Let us substitute $y=x-2$ in $y=-2 x+7$ , we get,

$x-2=-2x+7$

Adding both sides by 2x, we have,

$3x-2=7$

Adding both sides by 2, we get,

$3x=9$

Dividing both sides by 3,

$x=3$

Thus, the value of x is 3.

Substituting $x=3$ in $y=x-2$ , we get,

$y=3-2\\y=1$

Thus, the value of y is 1.

Hence, The solution of the equation is $x=3$ and $y=1$

4 0

3 years ago

Find the distance between the two points (-10,3) and (0,27)

crimeas [40]

Answer:

26 units

Step-by-step explanation:

$\boxed{distance \: between \: 2 \: points = \sqrt{ {(x1 - x2)}^{2} + {(y1 - y2)}^{2} } }$

Using the formula above,

distance between (-10, 3) and (0, 27)

$= \sqrt{ {( - 10 - 0)}^{2} + {(3 - 27)}^{2} }$

$= \sqrt{ {10}^{2} + ( - 24) {}^{2} }$

$= \sqrt{100 + 576}$

$= \sqrt{676}$

= 26 units

5 0

3 years ago

What is the measure of ∠C in the figure below

sertanlavr [38]

Answer:

C. 56°

Step-by-step explanation:

An isosceles triangle has two sides that are equal. ∆ABC has two equal sides. Thus, the angles opposite the two sides of an isosceles triangle are also congruent to each other.

<C and <A are congruent to each other.

m<A = 56°, therefore,

m<C = 56°

4 0

3 years ago

Given the following rectangle and circle, at what approximate value of x are the two areas equal? Show work and explain all step

suter [353]

Answer:

x ≈ 1.28

Step-by-step explanation:

I just took the exam:

Area of rectangle =(3x-1)(x+6), Area of circle = PI(x+1)^2. If you graph these and find where they intersect, you will get x ≈ 1.28.

I hope this helped! :)

7 0

3 years ago