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avanturin [10]
3 years ago
9

A driver was at 60m below sea level. the driver swam up 2m every 5 seconds.explain whether the driver would have reached the sea

surface after 2 minutes.
Mathematics
1 answer:
Luda [366]3 years ago
7 0

Answer: No


Step-by-step explanation:

The diver is at 60m below sea level, and swims upward 2m every 5 seconds.

So, since there are 24 five-second periods in 2 minutes (60secs/min), the diver would have swam up 48m after 2 minutes.

Since 60m - 48m is 12m, the diver has not yet reached the sea surface.

Hope it helps :)

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16 because if each chair has 4 legs you multiply that by the amount of chairs you have. 4x4=16

Step-by-step explanation:

4x4=16

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Expanded Form: 50 + 7 + 0.03 + 0.006

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What is in the following sequence - 6, - 14 - 22,-30​
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-6,-14,-22,-30,-38,-46
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3 years ago
Does anyone know this?
Stels [109]

Every hexagon clearly has 6 sides. Nevertheless, every time you "glue" two hexagons together, you "lose" 2 sides to your count, because the sides where the two hexagons meet are not exterior sides anymore, and so they are not taken into account in our counting.

Also observe that with n hexagons you have n-1 points of contact between hexagons.

Since every hexagon has 6 sides and every gluing point takes away 2 sides, the number of exterior sides with n hexagons is

s(n)=6n - 2(n-1) = 6n-2n+2=4n+2

Let's plug some values for n:

  • s(1) = 4\cdot 1 + 2 = 4+2 = 6
  • s(2) = 4\cdot 2 + 2 = 8+2 = 10
  • s(3) = 4\cdot 3 + 2 = 12+2 = 14
  • s(4) = 4\cdot 4 + 2 = 16+2 = 18

You can check that these values are correct by counting the sides on the figure you have.

Finally, we can count the sides of a train with 10 hexagons by plugging n=10 in our formula:

s(10) = 4\cdot 10 + 2 = 40 + 2 = 42

Note: the numbers we've given are the number of sides that form the perimeter. So, the actual perimeters are the number of sides multiplied by the length of the side itself: if we let s be the length of the side, the perimeters will be 6s,\ 10s,\ 14s,\ 18s for the first 4 trains, and 42s for the 10-hexagon train.

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